help allocating 2d array w/ new

WHY does this code not compile???:

Code:

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field_origin = new u8[field_size*6][field_size*10];

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Thanks for your help

>WHY does this code not compile???
Sadly, you can't do what you're trying to do. To simulate a two dimensional array, you need to create an array of pointers and then for each pointer, create an array of T:

Code:

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int **a = new int*[10];
for ( int i = 0; i < 10; i++ )
  a[i] = new int[10];

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Or you could save yourself some calls to new:

Code:

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int *a = new int[10 * 10];

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But that isn't as handy when it comes to syntactic sugar and resizing.

At least this works in MS Visual C++ if you initialize the pointer to the same type as the 2 d array it will accept it.

U8 (*field_origin)[field_size*10]; will create a pointer that is the same type as your array. field_size must be a constant though for it to work. I think U8 is equal to data type _int64 anyway here is the code i got to compile.

Code:

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        const int field_size=5;
        _int64(*field_origin)[field_size*10]=new _int64[field_size*6][field_size*10];

        field_origin[0][0]=20;

        int number=field_origin[0][0];
        cout<<number;
        delete [] field_origin;

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