2d array problem with vc++

Hi, I am new to Visual C++.

I have a 2d array in my function.
char array[MAX][MAX];

I then fill in the contents of the array, say, like this:
array[0][0]='a';
array[0][1]='b';
array[0][2]='\0';

Now when I run the debugger and want to view the contents of the 2D array,
I don't see them.
If I type this in my watch window:
array[0]
it says "error: index 0 out of bounds for pointer/array 'array' "
same error comes up if I type something like this in my watch window:
array[0],4

Can anyone tell me what I am doing wrong? I really need to be able to view contents of my 2d array!

Thanks for any ideas.

Quote:

---

Originally posted by LiLgirL
Hi, I am new to Visual C++.

I have a 2d array in my function.
char array[MAX][MAX];

I then fill in the contents of the array, say, like this:
array[0][0]='a';
array[0][1]='b';
array[0][2]='\0';

Now when I run the debugger and want to view the contents of the 2D array,
I don't see them.
If I type this in my watch window:
array[0]
it says "error: index 0 out of bounds for pointer/array 'array' "
same error comes up if I type something like this in my watch window:
array[0],4

Can anyone tell me what I am doing wrong? I really need to be able to view contents of my 2d array!

Thanks for any ideas.

---

type what in your watch window??
array[0] !!!!

for sure it won't work ... you are working on 2d array not 1d array


but can you simply tell me what is your program about and what is required from the program so it can be more clear?

well basically, i am trying to fill in a 2d array.

when i run the debugger i just want to be able to view its contents.

how do i do that?

Quote:

---

Originally posted by LiLgirL
well basically, i am trying to fill in a 2d array.

when i run the debugger i just want to be able to view its contents.

how do i do that?

---

you want to fill a 2d array
well lets consider ur array is called array1[5][3] .. or the size you wish

to fill array1 do the following

Code:

---


for (int i=0;i<5;i++)
 {
    for (int j=0;j<3;j++)
    {

      cout<<"enter the number \n";
      cin>>array1[i][j];
    }
}

---

this is in order to fill 2d array of dimensions 5 and 3

in order to display the first row on screen for instance

Code:

---


for(j=0;j<5;j++)

        cout<<array1[0][j]<<" ";

---

yea...i know how to print it and view the contents, but i want to know how to view the contents in the watch window of vc++.

doing array[0][0] wont do it. :(

excuse me but what do u mean by Watch window?

In Visual C++ 6.0, I was able to see "ab" when I put array[0] into my watch window while running the code below:

Code:

---

int main()
{
    const int MAX = 4;
    char array[MAX][MAX];

    array[0][0]='a';
    array[0][1]='b';
    array[0][2]='\0';

    int checkWatchWindow = 3;
}

---

So it might be some other problem with your code. Maybe you should post more of it.

-------

M_Ghani, the watch window is something in the Visual C++ debugger which allows you to see tha value of a variable while the program is running. LiLgirL sounds like she (or he) is using it correctly, but there is some other problem.

Ok, I made a new project with just your main fn, jlou. It still gaves the same error in my watch window. I am using vc++.NET...maybe thats a problem?

:(

Sorry, I don't have .NET handy to test on. Maybe somebody else can try it out. Did you try &(array[0]) or &array[0]?

using the following code:

Code:

---

#include "stdafx.h"

int _tmain(int argc, _TCHAR* argv[])
{
        const int MAX = 4;
    char array[MAX][MAX];

    array[0][0]='a';
    array[0][1]='b';
    array[0][2]='\0';
       
        return 0;
}

---

and the watch - array[0]. I could see all the characters being copied into the array by pressing f11. So I do not know why you are having the problem.

I finally got it to work by using a win32 console project.

I've been using console application (.NET) and it didn't work there..

Thanks for the ideas, people!