passing a 2dim array to a funct

Code:

---

int funct(char *[][])

---

something like this won't work, and the books that i have don't really go into the subject. any help would be appreciated. thanks in advance.

by doing that you are actually passing through a 3d array. If you want to pass in a 2d do this:

Code:

---

void foo( char p[][100] )
{
    //
}

---

where 100 is the size of the second dimension.

edit: the 100, could be any number and SHOULD be the size of YOUR array's second dimension

great! i thought i had seen something like that somewhere, but i just couldnt recall it. thanks again.

> could be any number and SHOULD be the size of YOUR array's second dimension
All minor dimensions MUST match.

There are 3 different ways of writing the same thing when it comes to passing multi-dimensional arrays to functions.

Code:

---

/* all these are the same */
void foo( char p[50][100] );  /* size of 1st dim is entirely optional */
void foo( char p[][100] );
void foo( char (*p)[100] );  /* watch the (), char *p[100] is a different animal */

---

This is handy, because the first one permits a rather simple and dead easy to remember rule called "copy and paste"

If you had
int arr[X][Y][Z];

You can simply copy and paste that into a function parameter
void foo ( int arr[X][Y][Z] );

And call it with
foo( arr );

Just like you would do for any non-array type really :)

If you want to go round chopping the X out of the function definition and declaration, then that is up to you. Though some lint tools will remark that the X size is redundant.