Initializing a 3D array w/o a loop.

What's the syntax? For example, a 2d array:

Code:

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int[][] array = {
              {2, 5} , {7, 4},                       
          };

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I'm looking for a similar approach with a 3D array but can't seem to find it anywhere.

same way, but it starts to get messy and hard to follow...

Code:

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int array [2][2][2]=
{
  {
    {1,1},
    {1,2}
  },{
    {2,1},
    {2,2}
  }
};

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yeah 3d arrays are pain in the ars. What are you trying to do with them funkydude?

Quote:

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Originally posted by axon
yeah 3d arrays are pain in the ars. What are you trying to do with them funkydude?

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I'm making Tetris, I need a 3d array to represent each block and it's rotations. I realize I could of just calculated the rotation myself using just a 2d array also, but I decided to go this way.

a 3d array is the hard way of going about it dude. Do it in 2d and figure out the rotation there. If you're having troubles do a search....this has been done many times here before.

Also, remember that in memory, the data is laid out just as it would be if it were a one-dimensional array. You can see this for yourself by simply casting the base of the array to a pointer of the appropriate type:

Code:

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 const int X = 4, Y = 2, Z = 5;

 int abc[X][Y][Z] =
  { { { 1,  2,  3,  4,  5 }, { 6,  7,  8,  9, 10 } }, 
    { {11, 12, 13, 14, 15 }, {16, 17, 18, 19, 20 } },
    { {21, 22, 23, 24, 25 }, {26, 27, 28, 29, 30 } },
    { {31, 32, 33, 34, 35 }, {36, 37, 38, 39, 40 } } };
 
 int main()
{
    for(int x = 0; x < X; ++x)
      for(int y = 0; y < Y; ++y)
        for(int z = 0; z < Z; ++z)
          printf("%d...", abc[x][y][z]);   


 const int U = X * Y * Z;

 int * r = (int*)abc;
 
 printf("\n\n - again - \n\n");   
 
 for(int u = 0; u < U; ++u)
  printf("%d...", r[u]);   
 
 return 0;
}

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