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Im confused. I need to write a program that takes a user input number and converts it into binary, octal, and hexidecimal.
The stack is to be set up as a class.
6/2 = 3 remainder = 0
3/2 = 1 remainder = 1
1/2 = 0 remainder = 1
110 is the binary equivalent of decimal 6
Any help to get started would be appreciated....thanks in advance
For 6 the process would be like this: (using 4 places)
Starting from the most significate place
2^3 = 8. 6>= 8? No. 0.
2^2 = 4. 6>= 8? Yes 1. 6-4 = 2;
2^1 = 2. 2>= 2? Yes 1. 2-2 = 0;
2^0 = 1. 0>= 1? No. 0
Answer: 0110
Lets try the number 9
2^3 = 8. 9>=8? Yes. 1. 9-8 = 1;
2^2 = 4. 1 >=4? No. 0.
2^1 = 2. 1>=2? No. 0.
2^0 = 1. 1>=1? Yes 1. 1-1 = 0;
Answer: 1001
For hex its often simpiler to just convert to binary and then convert to hex.
Bin to Hex:
0000 - 0x0
0001 - 0x1
0010 - 0x2
0011 - 0x3
0100 - 0x4
0101 - 0x5
0110 - 0x6
0111 - 0x7
1000 - 0x8
1001 - 0x9
1010 - 0xA
1011 - 0xB
1100 - 0xC
1101 - 0xD
1110 - 0xE
1111 - 0xF
Your first task is apparently to write a stack class, since you're probably not allowed to use the standard one.
I recommend you use an array
int _data[32];
and wrap it with a class which tracks the current top of the stack and provides methods to push and pop values.
This stack can hold at most 32 values, but that's ok, because an int has only 32 bits, which means that unless your program is supposed to work with numbers > 2^32 you're ok.
First push all the remainders on the stack:
Then make another loop to pop each item from the stack and print until the stack is empty.Code:do {
Stack.push(num%2);
num /= 2;
} while (num > 0);