whats wrong with the if statments

Code:

---

#include <iostream.h>
#include <stdlib.h>
#include <string>

int main()
{
      int watdoyousee    ;
      cout <<"filler V0.1 unregistert version\n";
      cout <<"\n\n\n\n\n";
      cout <<"1.unpack\n";
      cout <<"2.pack\n";
      cin>>watdoyousee      ;

      if  (watdoyousee == 1);
      {
      cout <<"dombo\n\n";
      }
      if (watdoyousee == 2);
      {
      cout <<"goedso\n\n";
      }
      return main();
}

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the problem if the outputs come
it wil say when you do 1

dombo

goedso

also with 2

You need to use switch satements.

i wil look that up in my book
thanks for the help

Code:

---

int main()
{
      int watdoyousee    ;
      cout <<"filler V0.1 unregistert version\n";
      cout <<"\n\n\n\n\n";
      cout <<"1.unpack\n";
      cout <<"2.pack\n";
      cin>>watdoyousee      ;

      if  (watdoyousee == 1); <-- take off the semicolon
      {
          cout <<"dombo\n\n";
      }
      if (watdoyousee == 2); <-- take off the semicolon
      {
          cout <<"goedso\n\n";
      }
      return main(); <-- change it to return 0
}

---

that works just taking of the ; selicoms

Your returning the function main() to an integer???

Listen to what alphaoide said, main will return 0.

Also, you only need 1 include. <iostream> (drop the .h, they are depricieted)

Code:

---

#include <iostream>

using namespace std;

int main()
{
      int watdoyousee;
      cout <<"filler V0.1 unregistert version\n";
      cout <<"\n\n\n\n\n";
      cout <<"1.unpack\n";
      cout <<"2.pack\n";
      cin>>watdoyousee;

      if  (watdoyousee == 1)
      {
          cout <<"dombo\n\n";
      }
      else if (watdoyousee == 2)
      {
          cout <<"goedso\n\n";
      }
      else
      {
          cout << "Unknown option '" << watdoyousee << "'\n";
      }
      return 0;
}

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