Simple step part of calculus problem

I have to solve for a.....pethagoryam (sp?) theorem......I forgot how to do this......please help.

Pythagorean ;)

Just use the quadratic formula for equations of the form ax^2+bx+c=0.

Namely, x = (-b + sqrt(b^2 - 4ac))/ (2a) and (-b - sqrt(b^2 - 4ac))/ (2a)

Thank you...Jesus how could I have not though about this.

tk tsk tsk!!!! its + or - the square root;)

Notice the two solutions. ;)

doh! slap me for not completely reading it

Pythagorean... isn't that

(a*a)+(b*b)=(c*c) if it's a right curve or something? I don't know how to say in English :|

a right angle

Quote:

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Originally posted by Felix
Pythagorean... isn't that

(a*a)+(b*b)=(c*c) if it's a right curve or something? I don't know how to say in English :|

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Yep