Outputting a menu

This program is supposed to be a menu system for holiday destinations. As you can see, no menu is displayed, but the user simply has to press a letter and the name of the country is displayed as destination.
So, could anyone give me a better way to output my program?

Code:

---

//---------------------------------------------------------------------------
#include<conio>
#include<iostream>
#include<cstring>
#pragma hdrstop
using namespace std;

//---------------------------------------------------------------------------

#pragma argsused
int main(int argc, char* argv[])
{
  char choice;

  while ( ( choice = cin.get() ) != 'q' )
  {
  cin.ignore();
  switch ( choice )

  {
  case 'a':

  cout << "Chosen destination is Australia" << endl;
  break;

  case 'u':

  cout << "Chosen destination is United States" << endl;
  break;

  case 't':

  cout << "Chosen destination is Thailand" << endl;
  break;

  case 'f':

  cout << "Chosen destination is France" << endl;
  break;

  case 'g':
  cout << "Chosen destination is Germany" << endl;
  break;

  default:
  cout << "Invalid Choice" ;
  }
  }

  return 0;
}
//---------------------------------------------------------------------------

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There's probably better ways with iterators etc, but here's one attempt:

Code:

---

#include <iostream>

using namespace std;

const string Options[] =
{
  "Destination 1",
  "Destination 2",
  "Destination 3",
  "Destination 4"
};

int main(void)
{
 
  for (int i = 0; i < sizeof(Options)/sizeof(Options[0]); i++)
  {
    cout <<Options[i] <<endl;
  }
}

---

i dont think class string supports the '<<' operator for cout

so either add this:

Code:

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ostream& operator<<(ostream& out, string& str)
{
    out<<str.c_str();
    return out;
}

---

or when u cout the string do

Code:

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    cout <<Options[i].c_str()<<endl;

---

-LC

Quote:

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Originally posted by Lynux-Penguin
i dont think class string supports the '<<' operator for cout

---

Actually, I think '<<' works fine with string. It worked for me in MSVC 6.0. If you use the deprecated header then you will get a compile error, but if you use <iostream> like Hammer did in his example it should work fine.

cout << is most deffinatly overloaded for std::string's. It would be silly not to.

>>i dont think class string supports the '<<' operator for cout
Are you seriously suggesting I'd post an answer using code that doesn't compile :rolleyes: :p

Quote:

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Originally posted by Hammer
Are you seriously suggesting I'd post an answer using code that doesn't compile :rolleyes: :p

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:) That's funny, especially considering the posted code doesn't compile :D . . . (requires #include <string> for me)