Getting three of a kind

I am wondering how to roll three of a kind out of three dice.

Does each dice have to be random? Would I use a switch?

It will be good for us to discuss if you define your problem correctly

Roll three dice. Count how many times it takes to get five 3-of-a-kinds.

That is basically it. I don't have code. The only thing I have written is throwing a pair a thousand times and counting the face value. I am trying a different prog now though.

I tried a search and came up short.

I just wrote up something quick based on what you helped me with... am I even headed in the right track?

Code:

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#include <stdio.h>

int main(void)

{

 int three_of_a_kind;
 int d1;
 int d2;
 int d3;

 printf("Rolling three dice: \n\n");


d1 = rand() % 6 + 1;
d2 = rand() % 6 + 1;
d3 = rand() % 6 + 1;
if (d1 == d2 && d2 == d3) {
  three_of_a_kind++;

 
 
 } 
 printf(" 1%18d\n", d1);
 printf(" 2%18d\n", d2);
 printf(" 3%18d\n\n", d3);
 
 return 0;
}

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Ok here is my final product

Code:

---


#include <stdio.h>

int main(void)

{

 int three_of_a_kind=0;
 int d1;
 int d2;
 int d3;
 int iRoll=0;

 printf("If you roll three dice: \n\n");

 while (three_of_a_kind<5)
 {
        iRoll++;
        d1 = rand() % 6 + 1;
        d2 = rand() % 6 + 1;
        d3 = rand() % 6 + 1;
        if (d1 == d2 && d2 == d3)
        {
        three_of_a_kind++;
        } 
 }
 printf("It takes %d rolls to get five three-of-a-kinds.\n\n", iRoll); 
 
 return 0;
}

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Thanks for your help Salem. You told me exactly what I needed to hear. :cool:

Code:

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It takes %d rolls to

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Being nitpicky but should it be "It took ... " :)

Also to avoid getting the same results every time, you need to seed the random number generator. The most common way is to do:

Code:

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srand ( time (NULL) );

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which requires #include <time.h>
Some also do:

Code:

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srand ( unsigned time (null) );

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>srand ( unsigned time (null) );
Then when that doesn't work, they do this:

Code:

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srand((unsigned)time(NULL));

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;)

Doh yea forgot the () around unsigned. I never use it so I was going off of old memory.