GMT Time

I need to get the time in GMT, so I used this:

Code:

---

#include <iostream>
#include <windows.h>
#include <string>
#include <time.h>


using namespace std;

int main()
{
        time_t now;
        struct tm *tm_now;
        struct tm *tm_gmt;
        char buff[BUFSIZ];

        now = time ( NULL );
        tm_now = gmtime(&now);

        strftime ( buff, sizeof buff, "%a, %d %b %Y %H:%M:%S %Z", tm_now );
        printf ( "%s\n%s\n", buff );

        return 0;
}

---

This code is straight from the FAQ, and it said to use gmtime() to get the time as GMT. But when I run that code, I get it in australian standard time. Does anyone know what went wrong, or an alternative way to get the time as GMT?

Maybe this example will help:

Code:

---

#include <iostream>
#include<ctime>

using namespace std;       

int main()
{
        struct tm *newtime;
        long time_var;
       
        time(&time_var);
        newtime = gmtime( &time_var );

        printf( "Coordinated universal time is %s\n",
                              asctime( newtime ) );
        return 0;
}

---

asctime() converts a tm time structure to a character string.

Well Salem I compiled that and got this:

GMT=Mon, 04 Aug 2003 09:01:08 Cen. Australia Standard Time
Local=Mon, 04 Aug 2003 18:31:08 Cen. Australia Standard Time

I'm running Windows 2000 and compiling with MSVCC 6.0

Damn australian computers, we're so secluded on our little island, we know nothing of the outside world, including time zones.

Do you know of any other functions/API's I could use to get the time? I'm about to search MSDN, and if that fails I'll try google... but I always thought the time functions were standard C++, no idea why they dont work.

Edit: Hey, I never realised the numbers were different. It must use GMT but still says the australian time zone. Oh well no matter, it works well enough so thanks very much guys!

The code from the faq works. I ran this:

Code:

---

#include<iostream>
#include <ctime>
#include <cstdio>

using namespace std;       

int main ()
{
  time_t now;
  struct tm *tm_now;
  char buff[BUFSIZ];

  now = time ( NULL );
  tm_now = gmtime ( &now );

  strftime ( buff, sizeof buff, "%A, %x %X %p", tm_now );
  printf ( "%s\n", buff );

  return 0;
}

---

And, I checked the result against the GMT clock at the bottom of this page:

http://greenwichmeantime.com/

and the results were correct. Where does the result say anything about Australian standard time?

I ran that on VC++ 6.0.

Curious, I get the same results as you Stovellp.. the times are correct, yet it insists on adding the Cen. Australia Standard Time

GMT=Mon, 04 Aug 2003 09:15:02 Cen. Australia Standard Time
Local=Mon, 04 Aug 2003 18:45:02 Cen. Australia Standard Time

Using Visual C++ .NET and Windows XP and my current location... Australia. :)

Yes, setting ones clock to GMT +05:00 Ekaterinburg (don't ask me, I have no idea where it is), produces these results.

Quote:

---

GMT=Mon, 04 Aug 2003 09:43:00 Ekaterinburg Standard Time
Local=Mon, 04 Aug 2003 15:43:00 Ekaterinburg Daylight Time

---

Does sound like somethings broken doesn't it? :)