convert char to binary???

Hi guys,

Is there a standard lib func that convert a char to binary value?

A char is inherently a binary value, as are all variables.

Code:

---

printf("%c%c%c%c%c%c%c%c",
  (ch&0x80)?"1":"0",
  (ch&0x40)?"1":"0",
  (ch&0x20)?"1":"0",
  (ch&0x10)?"1":"0",
  (ch&0x08)?"1":"0",
  (ch&0x04)?"1":"0",
  (ch&0x02)?"1":"0",
  (ch&0x01)?"1":"0"
);

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In the above code, "1" and "0" should be '1' and '0', respectively, to match the format specifiers passed to printf.

Hi,
Either you use & operator or use standard logic to do this. I have made in standard logic. just call this func.

Code:

---

char*  chartobin(int c)
{
        static char binarr[16];
        int i;
        for(i=1;i<=15;i++)
        {
                binarr[i]=c%2;               
                c=c/2;               
        }
        return binarr;
}

---

Code:

---

char*  chartobin(int c)
{
        static char binarr[16];
        int i;
        for(i=1;i<=15;i++)
        {
                binarr[i]=c%2;               
                c=c/2;               
        }
        /* null terminator required to make binarr a string */
        return binarr;
}

---

An int is not necessarily 16 bits. And you would need an extra char for the null byte if you want binarr to be a string.

In C, arrays are indexed starting from zero.

The usual idiom is i < 16 (to correspond with the above code).

One way to "convert char to binary" might be as follows.

Code:

---

#include <stdio.h>
#include <limits.h>

char *foo(char *dst, unsigned char value)
{
  unsigned char bit;
  char *start = dst;
  for ( bit = 1 << (CHAR_BIT - 1); bit; bit >>= 1 )
  {
      *dst++ = value & bit ? '1' : '0';
  }
  *dst = '\0';
  return start;
}

int main(void)
{
  unsigned char u = 117;
  char b [ CHAR_BIT * sizeof(u) + 1 ];
  printf("u = '%c' = 0%o = %d = 0x%X = \"%s\"\n", u, u, u, u, foo(b, u));
  return(0);
}

/* my output
u = 'u' = 0165 = 117 = 0x75 = "01110101"
*/

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>A char is inherently a binary value, as are all variables.
Yes, but a char is not always 8 bits.

>just call this func.
And this works for you? This may work better:

Code:

---

#include <limits.h>

char *chartobin ( unsigned char c )
{
    static char bin[CHAR_BIT + 1] = {0};
    int        i;

    for ( i = CHAR_BIT - 1; i >= 0; i-- )
    {
        bin[i] = (c % 2) + '0';
        c /= 2;
    }

    return bin;
}

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im trying to get two input from user (enter character one) (enter charater two) then i would like to get it converted to binary then display the hamming distance between two characters how would i do that..

Quote:

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Originally Posted by saravana

im trying to get two input from user (enter character one) (enter charater two) then i would like to get it converted to binary then display the hamming distance between two characters how would i do that..

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You should create a new thread instead of bumping a thread that is 6 years old.