A class pointer to the class I come from

I have the following class:
[tag]

Code:

---

class myGui
{
public:
  MyWidget w;                                       
  swmArray s;
  GearWidget g;
  quitDialog q;         
  int browseNum;
  DirectoryWindow mw[20];
public:
  myGui(void);
};

---

[/tag]
I want the members (which are other classes I made) to have a pointer to the instance of myGui to which they are a member.

For example in the class MyWidget I wish to have a member "myGui *mypointer;" thats points to the instance of myGui that contains my instance of MyWidget.

You see the problem. They will #include each other. How do I go about this?

-- Paul

If you need to, put class Widget; or whatever other class you have in front of everything so that you can use pointers to any class before the classes are actually defined.

ie:

Code:

---

class A;
class B {
  A* func();
};
class A {
  //...
};

---

If you want your member objects to contain a pointer to the object they are a member of, use a constructor. Pass 'this' to each object that way. ie:

Code:

---

class Widget { //...
private:
  Widget();  //this makes sure that the only possible constructor is the bottom one
// You may want to declare a copy constructor to be safe
  Container* parent;
public:
  Widget(const Container* b) : parent(b) {}
};
class Container {
public:
  Widget object;
  C object2;  //some other widget
  Container() : object(this), object2(this) {}
}

---

I'm not sure but I think some of the A's and B's are mixed up the second example. Are they?

Quote:

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Originally posted by Lumber606
I'm not sure but I think some of the A's and B's are mixed up the second example. Are they?

---

Yep... I fixed them now. Thanks for checking the code.

>> If you need to, put class Widget; or whatever other class you have in front of everything so that you can use pointers to any class before the classes are actually defined.

Aka 'forward declarations'. :)

Note, it could be a pointer or a reference with just the forward declaration.