Passing a row of a Multidemensional Array to a function

Let's say I have 2D array of N rows and M columns, how do pass one of the rows of this array to a function and the function can use this row as a 1D array? Thanks.

Code:

---

void foo( data_type array[SIZE] )
{

}

...

data_type array[ROWS][SIZE];

foo( array[x] );

---

Enjoy.

Quzah.

>>>void foo( data_type array[SIZE] )
when defining this function, do I must specify the array size as SIZE (here it corresponds to number of columns) ?

Passing a row to it is actually passing a pointer to the first element in whatever row. The size specifier was really just for illustration. Consider the following:

Code:

---

#include <stdio.h>
#define SIZE 10

void foo( char array[] )
{
    printf("array is: %s\n", array );
}

int main( void )
{
    char mdarray[][SIZE] =
    {
        "foo",
        "bar",
        "barfoo",
        "fweeeeee",
        "the end",
        0
    };
    int x;

    for( x = 0; mdarray[x][0]; x++ )
        foo( array[x] );

    return 0;
}

---

This should run through the list and stop when it hits the null (the zero).

Quzah.

Way back when...quzah wrote:

Code:

---

    for( x = 0; mdarray[x][0]; x++ )
        foo( array[x] );

    return 0;

---

was array[x] supposed to be mdarray[x]?

Regards,
Dave

Yes. Way to necro a six year old thread!


Quzah.