newbie question - checking if a char array stores a number.

Hi
Yeah, it sounds like a strange thing to do " checking if a char array stores a number", and your probably wondering why there'd be a number there anyway. Well, trust me, there is a reason.

The thing that's confusing me, is that I assumed it would be simple enough to check if there was a specific number in a char array like so:

Code:

---

for ( i=0 ; i<stringlength ; i++){
        if ( string[count]==1 ){
                    printf("One.\n");
        }
}

---

What i'm actually trying to do is a little more complicated than that, but that's the problem simplified. For some reason it's just reading straight passed any 1's and continuing on without printing "one".
I also tried casting it (string[count]) to an integer, but still had no luck.

Please help me out. :)

Thanks,
turmoil

Shouldn't the array index be i not count?

eeer yeah . whoops. count is what i'm using in my actual code, so i got a little distracted making that example....

so i meant:

Code:

---

for ( i=0 ; i<stringlength ; i++){
    if ( string[i]==1 ){
                    printf("One.\n");
    }
}

---

But either way, it still doesn't read any 1's in the string, when there definately are 1's there (amongst the char's).

if( string[i] == '1' )

Quzah.

And a more general way is to include ctype.h and then use isdigit()

if(isdigit(myarray[index]))
.. do something

hey thanks heaps quzah! That's all i needed. :)

(Can't use isdigit as i'm looking for specific numbers.)

cheers,
tumoil