charactor count wthout getche function..?

#include<stdio.h>
#include<conio.h>
void main()
{
int count=0;
printf("\n\tType any phrase");
while(getche() !=13) //13 is For enter key
{
count++;
}
printf("\nCharactor count is =%d",count);
getch()
}
out put

Type any phrase
CAT
charactor count is 3

i want to count the charactors without using the getche() function. Is there any way to make the program to count the charactors without using getche()..? if yes then please write the programmm.i shall be soo much thankful to you.
thanks in advance...

Code:

---

#include <string.h>
#include <stdio.h>
#include <stdlib.h>

main( ) {

    char word[ 64 ];

    printf( "Enter the word: " );
    scanf( "%s", word );

    printf( "The # of characters is %d", strlen( word ) );

    system( "pause" );

}

---

You could use the strlen function (remember to put the string.h header file) to read the number of characters. Example:

Code:

---

#include <stdio.h>
#include <string.h>

int main()
{
    char phrase[150];        \\array size
    int size;

    printf("Type any phrase: ");
    scanf("%s",&phrase);  \\you can also use gets if you want
    size=strlen(phrase);
   
    printf("The size of the phrase is: %i",size);

    return 0;
}

---

This snippet outputs all the characters in a file. I'll leave it to you to change it to count them instead. Of course, as it is, it outputs spaces, number and characters alike. You might want to only be counting characters (for example):

Code:

---

int c;
 
while ((c = fgetc(fp)) != EOF)
{
  putchar (c);
}

---

Also, read this