Slope to degrees

Does anyone know how to compute the azimuth in degrees from the given slope. If the two components (the numerator and the denominatory or x component and y component) are known. This is what I have but I am not sure that it is correct.

Code:

---

double ComputeAzimuth(double dbY, double dbX)
{
        int iQuadrant = 0;
        double slope;

        slope = dbY/dbX;


        if( dbX > 0 && dbY > 0)
        {
                iQuadrant = 1;
        }
        else if( dbX < 0 && dbY > 0)
        {
                iQuadrant = 2;
        }
        else if(  dbX < 0 && dbY < 0)
        {
                iQuadrant = 3;
        }
        else if(  dbX > 0 && dbY < 0)
        {
                iQuadrant = 4;
        }

        switch( iQuadrant )
        {
                case 1: return 90 - (atan(slope) * (180/PI));
                case 2: return 270 - (atan(slope) * (180/PI));
                case 3: return 270 - (atan(slope) * (180/PI));
                case 4: return 90 - (atan(slope) * (180/PI));
        }

        return 0.0;
}

---

By the way vertical and horizontal azimuths such as 0, 90, 180, 270 are treated as special cases so they don't need to be computed through this function.

if I understand your question properly, you wont to know how to calculate the inclination from the x axis of function.

m == slope
deg == Degree

so

inverse tan m = deg
tan deg = m

convert as need be

Hope this helps ;)

My understanding (different from wistlenm1) is that you want to calculate the bearing of a point {dbX, dbY} from the origin taking the positive y-axis as reference 0 degrees and measuring clockwise (like a compass bearing). If I am right in my understanding, then I reckon your code will give you the answer you want...