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this is the code
#include <iostream.h>
int mult(int x, int y);
int main()
{
int x, y;
cout<<"Please input two numbers to be multiplied: ";
cin>>x>>y;
cout<<"The product of your two numbers is "<<mult(x, y);
return 0;
}
int mult(int x, int y)
{
return x*y;
}
the codes fine i just want it to say pick another number then repeats the code again! Can any1 help me ?
Thankz
ICE
loops...
read more about loops, then you'll have a good idea of how to use for, while, or do/while loops.
Hmm..
Do something like this:
#include <iostream.h>
int mult(int x, int y);
int main()
{
int x, y;
char again;
cout << "Would you like to run the program?(y/n) " << endl;
cin >> again;
while (again == 'y') {
cout<<"Please input two numbers to be multiplied: ";
cin>>x>>y;
cout<<"The product of your two numbers is "<<mult(x, y) << endl;
cout << "Would you like to run the program again? (y/n) ";
cin >> again;
}
cout << "Thank you for trying my program. " << endl;
return 0;
}
int mult(int x, int y)
{
return x*y;
}
Sorry about not adding comments, but most of the code is pretty self explanitory.
Good luck,
Kavity
What about this?
#include <iostream.h>
#include <ctype.h>
int mult(int x, int y);
int main()
{
int x, y;
int sentinel = -1;
char choice;
do{
cout<<"Please input two numbers to be multiplied: ";
cin>>x>>y;
cout<<"The product of your two numbers is "<<mult(x, y);
cout << "\n\nEnter values again <Y:N>: ";
cin >> choice;
choice = toupper(choice);
if(choice != 'Y')
sentinel = 0;
cout << "\n";
}while( sentinel == -1);
return 0;
}
int mult(int x, int y)
{
return x*y;
}
Let him do what he wants. I was just stating an easy way to do it :D