declaring chars: char file[<nonconstant>] [1024];

is there any way to create an array of characters like this:

Code:

---

int numfiles;
cin >> numfiles;
char files[numfiles] [1024];

---

it says i need a constant variable up there, and i tried (const int)numfiles...:) lol, but of course, that didn't work

so, do i have to do a typedef or whatever that command is?

(sorry if this has already been asked)

that compiles w/out errors with mingw

well, this is in visual studio

ok, nevermind, i found out a way to do it (new, delete)

here:
#include <iostream.h>
#include <stdio.h>


void main()
{
char **t;
int size;

printf("size:");
cin>>size;

t=new char *[size];

for(int a=0; a<size; a++)
t[a]=new char[1024];

t[0]="Josh";

printf("%s\n",t[0]);
t[1][2]=60;
printf("%d\n",t[1][2]);

}

oook, here's what i got:

Code:

---

        int numfiles;
        cin >> numfiles;
        char *files;
        files=new char[numfiles*256];

---

and that creates it, to view stuff, i just do this:

Code:

---

        char filename[256];
        strcpy(filename,"blah.txt");
        for(int c=0;c<256;c++)
        {
                files[a*256+c]=filename[c];
                if(filename[c]=='\0')
                        break;
        }

---

and just for "good housekeeping"

Code:

---

        if(files)
                delete [] files;

---

Quote:

---

and just for "good housekeeping"

Code:

---

if(files)
        delete files;

---

---

That should read "bad housekeeping". Either that, or the code should read:

Code:

---

delete[] files;

---

deleting a NULL pointer has no effect, so checking for NULL before you call delete is inefficient.

ya and he forgot []

is there a small way to do it like that with two diynamics?

sorry, i forgot to put the [] in there......