quit the loop?

How can I stop the loop when user enter ESC? When user enters ESC, the program prompts user for entering Y/N, if Y, stops the loop, otherwise, the loop continue.

Code:

---

int i = 0;
do
{
  i++;
// many sub-programs follow, e.g.
  fun1();
  fun2();
  fun3();
  .........
  fun10();
}
while(i < 2000); // for example 2000

---

Because these many sub-programs involves a lot of computations and cannot stop or wait for user's input.
Useless the user press ESC, the loop should be continued to run.
I have no ideas of it.
Can anyone answer me?

Here is some info that will help you.

gg

it would also work doing this

Code:

---

#include <stdio.h>
#include <conio.h>
#define ESC 0x1b

int main ( )
{
 int i=5;
 do{
      printf("Press a key.\n");
      if(getch()==ESC){
        printf("You pressed Escape.\n");
        }
      else     
          printf("You didnt press Escape.\n");
       
      i--;     
      }
      while(i>0);
return 0;
}

---

Pretty much same way;)

I've try getch() that the program wait for user's input and cannot jump to
puts("After get ESC"); if no one hit keyboard.
How can I write an program that do not wait for user input?
The program only respond when user hit ESC, otherwise, the program still running.

Code:

---

int i = 0;
do
{
  i++;
  puts("Before get ESC");
  if(getch()==ESC){
      printf("You pressed Escape.\n");
  }
  else     
      printf("You didnt press Escape.\n");
  puts("After get ESC");

// many sub-programs follow, e.g.
  fun1();
  fun2();
  fun3();
  .........
  fun10();
}
while(i < 2000); // for example 2000

---

if i understand you then u can do just fine with kbhit...

do{
blabla();
}
while(!kbhit());

Yeah, what Fozzy said: use kbhit().

gg

You could use _kbhit() to check for a key press first. [edit on] As stated above [edit off]

Code:

---

#include <stdio.h>
#include <conio.h>
#define ESC 0x1b
 
int main()
{
    int i = 0, stop=0;
    while( i < 200000 && !stop )
    {
        if(_kbhit() && getch()==ESC)
        {
            stop=1;
            continue;
        }

        printf("PRESS ESC TO STOP %d\n", i);
//      many sub-programs follow, e.g.
//      fun1();
//      fun2();
//      fun3();
//      .........
//      fun10();
      i++;
    }
    return 0;
}

---