Reducing loops

Hello,

I got folllowing code working but need to work on optimization.

Can anybidy help me in reducing number of loops?

main()
{
int height,i,j,k;

while ( getch() == 'c' )
{
printf("Enter the height of triangle\n");

scanf("%d",&height);

printf("Height = %d\n",height);

k = 1;

for ( i = 0; i < height; i++)
{
j = height-i-1;

while ( j--)
putch(' ');
for ( j = 0; j < k ; j++)
putch('*');
printf("\n");
k = k+2;
}
k = 1;
for ( i = 0; i < height; i++)
{
j = i;

while ( j--)
putch(' ');
for ( k = (((height-i)*2)-1); k ; k--)
putch('*');
printf("\n");
k = k-2;
}
printf("\n\n\n Press 'c' to continue\n");
}
}

Please read this then edit your post accordingly.

Code:

---

main()
{
        int height,i,j,k;

        while ( getch() == 'c' )
        {
                printf("Enter the height of triangle\n");

                scanf("%d",&height);

                printf("Height = %d\n",height);

                k = 1;

                for ( i = 0; i < height; i++)
                {
                        j = height-i-1;
                       
                        while ( j--)
                                putch(' ');
                        for ( j = 0; j < k ; j++)
                                putch('*');
                        printf("\n");
                        k = k+2;
                }
                k = 1;
                for ( i = 0; i < height; i++)
                {
                        j = i;
                       
                        while ( j--)
                                putch(' ');
                        for ( k = (((height-i)*2)-1); k ; k--)
                        //for ( j = k ; j ; j--)
                                putch('*');
                        printf("\n");
                        k = k-2;
                }
                printf("\n\n\n Press 'c' to continue\n");
        }
}

---

Here's the first for loop rewritten to not use internal loops. See what you make of it and if you can apply its logic to the second loop.

Code:

---

for ( i = 0, k = 1; i < height; i++, k += 2)
{
  j = height-i-1;
  printf ("%*.s", j, " ");
  /* This next line limits the height of the triangle based on the
  * number of *'s in the string.
  *  Therefore, it is not as flexible as a loop
  */
  printf ("%.*s", k, "****************************************");
  putchar('\n');
}

---

Here's an idea:

Code:

---

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main( void )
{
        char *line = NULL;
        int linesize, size, front, back;

        printf("Enter the size of the pyramid: ");
        if( scanf("%d",&size) != 1 )
        {
            printf("You suck, go away.\n");
                exit( 0 );
        }

        linesize = size * 2 + 1;
        if( (line = malloc( sizeof( char ) * linesize )) == NULL )
        {
                printf("Your computer sucks, go away.\n");
                exit( 0 );
        }

        memset( line, ' ', linesize );
        line[linesize-1] = '\0';

        for( front = back = size; size > 0; size--, front--, back++)
        {
                line[back] = line[front] = '*';
                printf("%s\n", line );
        }
        free( line );
        getchar( );
        return 0;
}

---

Don't turn this in for homework please. I figured it's be an amusing work around. Enjoy.

[edit]You don't actually need the 'front' line here. You could just use size.[/edit]

Quzah.