How do I print from one function?

Code:

---


/*
This is a simplified outline of my program as it treats the display of
titles and messages: messages are printed from individual modules.  I want
to change the program by printing out all titles and messages from a single
module, calling this function as and when needed during the execution of the
program.
I have difficulty in grasping how this might be done: I want to call this
single print function from different modules and I want to display only one
particular message at each call to the function.
I have two questions:
1.How would I do this by passing a string (character array: char[]) as an
argument?
2.How would I use a pointer to do this?
*/

main()
{
  one();

  two();

  three();
}

one()
{
  printf("\nmessage 1");
}

two()
{
  printf("\nmessage 2");
}

three()
{
  printf("\nmessage 3");
}

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Are you looking for something like this:?

Code:

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void print_something(const char* something)
{
    printf(something);
}

---

This is exactly the same:

Code:

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void print_something(const char something[])
{
    printf(something);
}

---

gg

Yes, but I want all three messages to be in the print function & I want to print a different message in turn, calling it from its appropriate function (one, two or three).

clinamen

How about:

Code:

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void printme(const char *msg1, const char *msg2, const char *msg3)
{
  if (msg1)
    cout <<msg1;
  if (msg2)
    cout <<msg2;
  if (msg3)
    cout <<msg3;
)

... somewhere else ...

printme ("Message One", "Message Two", "Message Three");
printme ("Message One", "Message Two", NULL);
printme ("Message One", NULL, "Message Three");

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Thanks for this Hammer, I`ll try it out.

clinamen