convert from c to c++

How can I convert this program in c to c++ code?



/* itoa example */
#include <stdio.h>
#include <stdlib.h>

main ()
{
int i;
char buffer [33];
printf ("Enter a number: ");
scanf ("%d",&i);
itoa (i,buffer,10);
printf ("decimal: %s\n",buffer);
itoa (i,buffer,16);
printf ("hexadecimal: %s\n",buffer);
itoa (i,buffer,2);
printf ("binary: %s\n",buffer);
return 0;
}

#include <stdio.h>
#include <stdlib.h>

int main ()
{
int i;
char buffer [33];
printf ("Enter a number: ");
scanf ("%d",&i);
itoa (i,buffer,10);
printf ("decimal: %s\n",buffer);
itoa (i,buffer,16);
printf ("hexadecimal: %s\n",buffer);
itoa (i,buffer,2);
printf ("binary: %s\n",buffer);
return 0;
}

#include <iostream>
#include <cstdlib>

int main() {

int i;
char buffer[33];

cout >> "Please enter a number: ";
cin << i;

itoa( i , buffer, 10);

cout << "Decimal: " << i;

itoa(1, buffer, 16);

cout << "Hexadecimal: " << i;

itoa(i, buffer, 2);

cout << "Binary: " << i << endl;

return 0;

}

I'm pretty sure this will work.

Actually, I think it would be this

#include <cstdio>
#include <cstdlib>

int main ()
{
int i;
char buffer [33];
printf ("Enter a number: ");
scanf ("%d",&i);
itoa (i,buffer,10);
printf ("decimal: %s\n",buffer);
itoa (i,buffer,16);
printf ("hexadecimal: %s\n",buffer);
itoa (i,buffer,2);
printf ("binary: %s\n",buffer);
return 0;
}

:p

Honestly though, I actually have to check look up all the printf identifiers before I can read that code.

Come on. You C++er's can do better than that. Even I know that you can use:

string buffer;

And:

buffer + i;

But I have no idea how to replace the itoa functions. There must be methods that will do that.

is this what you mean?

Code:

---

#include <iostream.h>

int main ()
{
  int i;
  char buffer [33];
  cout<<"Enter a number: ";
  cin>>i;
  itoa (i,buffer,10);
  cout<<"decimal: "<<buffer<<"\n";
  itoa (i,buffer,16);
  cout<<"hexadecimal: "<<buffer<<"\n";
  itoa (i,buffer,2);
  cout<<"binary: "<<buffer<<"\n";
  return 0;
}

---

: error C2065: 'itoa' : undeclared identifier

add:
#include<stdlib.h>

Thanks, another question:

cout<<"octaldecimal: "<<buffer<<"\n";
itoa (i,buffer,8);


Is this the right code for octal?

Quote:

---

You C++er's can do better than that.

---

I think their point is that the code is c++ already. But if you wanted to use some exclusive c++ stuff you could do this -

Code:

---

#include <iostream>
#include <bitset>

using namespace std;

int main()
{

        int i;
    cout<<"Enter a number: ";
        cin>>i;
        bitset<32> bin(i);

        cout << "decimal: " << i << endl;
        cout << "hexadecimal: " << hex << i <<endl;
        cout << "binary: " << bin << endl;


        return 0;
}

---

For octal you can do -

cout << "octal: " << oct << i << endl;

Thanks a whole lot, it works.

Well I'll be damned. That's fantastic.