while loops with arrays

Code:

---

#include <stdio.h>
#include <math.h>

float average(int sum, int array_size);

float std(int sum, int array_size);

       
       

int main(void)

{
       
        int a[3] = {0};
        int b[3] = {0};
       
        int sum = 0;
        int i = 0;

        float av;
        float st;
        float av2;
        float st2;
       
        printf("Enter three numbers\n");
       
        while (scanf("%d", &a[i]) !=EOF)
        {
                sum += a[i++];

                if (i == 3)
                        break;
        }

        av = average(sum, i);
        st = std(sum, i);

        printf("\nThe average of the numbers you entered is %.2f\n",av);
        printf("\nThe standard deviation is %.2f\n",st);

        printf("\nEnter three more numbers\n");

        while (scanf("%d", &b[i]) !=EOF)
        {
                sum += b[i++];

                if (i == 3)
                        break;
        }

        av2 = average(sum, i);
        st2 = std(sum, i);

        printf("\nThe average of the numbers you entered is %.2f\n",av2);
        printf("\nThe standard deviation is %.2f\n",st2);

        return 0;
}
float average(int sum, int array_size)
{
        return (float) sum/array_size;
}
float std(int sum, int array_size)
{
        return (float) sqrt((pow(sum,2) + pow(sum/3,2))/array_size - 1);
}

---

Why isn't the second while loop working properly?

Hello, volk

Before the line:

printf("\nEnter three more numbers\n");

you have omitted to re-initialise variables i and sum to zero...

Cheers from MrB :)

Thank you very much. :)