declare references to references works!

Hi!

You cannot declare references at references (eg. int& &rr = r), but this way, it works:


„_int main(void)
„_{
„_ int a = 1;
„_ int &r = a;
„_ int &rr = r;
| rr++;
| cout << a; // output: 2!
|
|}


Why does this work!?
Depends it which compiler you are using?

regards,
Manuel

You can reference a reference a reference a reference a reference... =)

But why would you want to?

Quote:

---

Originally posted by ManuelH
Hi!

You cannot declare references at references (eg. int& &rr = r), but this way, it works:


„_int main(void)
„_{
„_ int a = 1;
„_ int &r = a;
„_ int &rr = r;
| rr++;
| cout << a; // output: 2!
|
|}


Why does this work!?
Depends it which compiler you are using?

regards,
Manuel

---

That's because you're not referencing a reference. You're just referencing the variable a again.

Every time you are trying to perform any operation with a reference, "Despite appearances, no operator operates on a reference. The reference always refers to the object it was initialized with".

Which just means that when ever you are trying to take a reference to (reference to an object), you are just taking reference to the object

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