Semicolon at end of class?

Why after you declare a class do you have to put a semicolon after the ending bracket?

B/C you can name an instance after the declartation...

class A{

}InstanceOfA;

EDIT: I forget if it's an instance or an Alias

Quote:

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Originally posted by OneStiffRod

EDIT: I forget if it's an instance or an Alias

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It's an instance of the class.

But I don't know about that being the reason for the semi-colon :rolleyes: :D

-Futura

Because you aren't implementing the class you are declaring it. Even though you are doing the

class CMyClass
{
int a, b;
};

method, you are really just declaring a type, kinda like a typedef. Oh, and you can make an instance of it as well, and the semicolon tells when you are done making instances.

in C, when you define a struct, you can name it at the end of the declaration. forgot exactly how, but im pretty sure the reason for the semicolon is the struct :).

Quote:

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Originally posted by Flikm
in C, when you define a struct, you can name it at the end of the declaration. forgot exactly how, but im pretty sure the reason for the semicolon is the struct :).

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That's just because of a typedef, you can do that with any datatype.

IE

typedef int Thing; // Makes Thing an alias for int

typedef struct { int a; } OtherThing; // Makes OtherThing an alias for that particular type of struct.

The reason for the semicolon, as people said, is just to show that you aren't creating any instances (or to show the end of the list of instances and/or pointers to instances, or arrays of instances, etc.)

Flik, the syntax is this:

Code:

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#ifndef _MAIN_H_
#define _MAIN_H_

#include <stdio.h>
#include <stdlib.h>

typedef struct _STRUCT
{
 int x;
 int y;
}STRUCT;

// Now if you wanted to make an instance you would use STRUCT as the data type not _STRUCT.

#endif

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yeah i looked it up. theres like 5 ways to do it. anyways, excuse my ignorance :).