Simple stuff!

I was thinking of making a simple program that tells how old you are.

So here is what I come to:


#include <iostream.h>

int main()

{

int age;

cout<<"Enter date you were born (4 digit):";

cin>>age;

cout<<"You are " <<2002-age "years old

}

Would it work?

Sorry, I don't got a compiler to tell you what I got.:(

>Would it work?
No.

>Sorry, I don't got a compiler to tell you what I got.
So why does it matter if it works or not? Try it when you get a compiler. :rolleyes:

-Prelude

close, but no cigar. Using slightly outdated syntax you could do something like this:

#include <iostream.h>

int main()

{

int age;
int year = 2002;


cout<<"Enter year you were born (4 digit):" << endl;

cin>>age;

cout<<"You are " << year - age << " years old " << endl;

return 0;

}

There are ways to jazz this up a little, but it should be a functional program as is.

Of course those programs only print an approximation of the persons age; to actually compute their age you would need to use the current month and day, and the birth month and day as well.

here's a possibility

Code:

---

#include <iostream.h>

int main(){

int birth_year,birth_month,birth_day;



//current date info
// ( in reality this should not be hardcoded )
int year = 2002;
int month = 12;
int day = 26;

cout<<"Enter year you were born (4 digit):";
cin>>birth_year;
cout<<"Enter month you were born (2 digit):";
cin>>birth_month;
cout<<"Enter day you were born (2 digit):";
cin>>birth_day;


int age = year - birthyear;
if(birth_month < month) age-- ;
else if(birth_month == month && birth_day < day) age-- ;

cout<<"You are " << age << " years old " << endl;

return 0;

}

---

I think that should work, but I haven't tested it so be warned that it may not.

I just want to be able to assume what the outcome will be without a compiler.

Yeah, I know, - never assume too much - :p

Dude, Liger86, why don't you have a complier? You can download one for free. You can't be a programmer without a compiler.

I got one at school that I experiment with but I'm gettin VC++ .net

So there:p

I dont think iostream could handle that expression and it would be considerable if the expression is replaced with a variable wich receive the result

Good luck~

Code:

---

#include <iostream>
using namespace std;

int main(){

int birth_year,birth_month,birth_day;

//current date info
// ( in reality this should not be hardcoded )
int year = 2002;
int month = 12;
int day = 26; //reflect current day

cout<<"Enter year you were born (4 digit):";
cin>>birth_year;

if(birth_year > 2002)
{
cout<<"Error:  You cannot be born after this year if you are using the program now.  See Einstein's clock theory for more details"<<endl;
}
if(birth_year <= 2002)
{
cout<<"Enter month you were born (2 digit):";
cin>>birth_month;
if((birth_month<0) || (birth_month>12))
{
cout<<"Error: In the standardized time format adopted some while ago, you cannot have a negative month or a month having a value more than 12 (unless you're referring to the Simpsons' \"Smarch\""<<endl;
}
if((birth_month>0) && (birth_month <= 12))
{
cout<<"Enter day you were born (2 digit):";
cin>>birth_day;
if(birth_day < 0 || birth_day > 31)
{
cout<<"Error: In the standardized time format adopted some while ago, you cannot have a negative day or a day having an integral value exceeding that of 31"<<endl;
}
else
{
int age = year - birth_year;
if(birth_month < month) age-- ;
else if(birth_month == month && birth_day < day) age-- ;
               
cout<<"You are " << age << " years old " << endl;
}
}
return 0;
}
}

---

Just as a little revision to beege31337's code, You might want to guard against negative/exceeding years, negative/exceeding days, and negative/exceeding months. This was hacked together quite quickly so I don't know if it'll compile, but it should work.

What do

Code:

---


<< endl;

---

do?

If I were in a bad mood, i'd say RTFM, but since you're new here, I'll explain.

When you're outputting a string of text or variables in C++, you normally use iostream to handle the output and input by using cout<< and cin>>. However, in the cout<< function, you can jump down by a line by using the \n switch inside a logical text string. Ex:

Code:

---

cout<<"Hello, let me skip a line downwards...\nHello!";

---

Because the \n switch doesn't flush the output buffer, it is commonly used in short, simple functions and programs. Since I was quickly hacking the code together, I didn't take that into consideration.

<<endl is used to flush the output buffer and jump a line downward in the data output. Whether you use it for big or small functions, it doesn't matter. However, it is generally considered correct in both cases, as it makes for a smaller compilation size and a better compiled footprint (if you're working with complex algorithms).

Ex:

Code:

---

cout<<"Hello, let me skip a line downwards..."<<endl<<"Hello!";

---