c++ char name;

how do I set it that I am able to enter more than one char ex:hello, right now all I can enter is ex: a, or b ect...

I just started programming.

Post code showing how you are reading-in single characters and then I can show you how to read in strings.

thanks for the quick response I'm not used to that.

here is the code

Code:

---

# include <iostream.h>
int main ()
{
int number;
char letter;
cout <<"please enter one letter."
cin >> letter;
cout << "please enter your age."
cin >> number;
cout << "this is the name you have entered." << letter;
cout << this is the age you have entered." << number;
return 0;
}

---

I was told to include <string.h> what is that supposed to do?

string letter

will that solve my problem?

char name[50];

cout<<"Enter your name: ";

cin.get(name, 50);

Or

char name[50];

cout << "Enter a name:";
cin >> name;
cout << "You entered:" << name << endl;

You should learn about strings, either as an array of char's or using the string library <cstring>

you can also do

scanf("%s",&name)
with char[30]


[30]-can be changed to any number but that might cause a glich when you enter more than your number in [].hope it helps

is this c++

Code:

---

char name;
          getline name;

---

and this regular c

Code:

---


        char name[50];
    cin name;

---

?????????????????????????????????????????????

Wrong. cin is an istream object. In other words it is a c++ class. Since this is C++ you should use a string. However, if speed and memory consumption is an issue (i doubt that it is here) then use a array. You can't hold a string in a single char. A char only holds 1 byte of data (one letter).

Quote:

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Originally posted by ammar
You should learn about strings, either as an array of char's or using the string library <cstring>

---

No, the string type is located in <string>
<cstring> is functionaly equivalent to <string.h>

I think ammar did mean cstring...