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Is it possible for them to return more than one value without using any advanced tools.
I tried to do it in this code, but only one value in the function was printed:
Code:#include<iostream>
int main()
{
float function(float,float);
float a=3.4,b=7.8;
cout<<a<<endl<<b<<endl;
cout<<function(a,b);
return 0;
}
float function(float a,float b)
{
a=32.2;
b=90.2;
return a;
return b; // I also tried "return a,b;" with no success
}
Using the key word return, you can only return one variable.
If you want to modify many variables, just pass them by reference.
A function can only return one value. To get around this restriction you have two options:
1) Return a struct or class that contains more than one value
2) Pass variable to the function by reference, meaning the function can change the value of the variables, but they are the same variables that were passed in and can be accessed again after the function call.
Hope that helpsCode:#include<iostream>
struct numbers{
float a;
float b;
float c;
};
numbers dummyFunct(numbers nums)
{
nums.a = 92.3;
nums.b = 77.654;
nums.c = 0.99;
return (nums);
}void funct(float &a, float &b)
{
a = 5.4;
b = 87.45;
}
int main()
{
numbers someNums;
someNums.a = 3.4;
someNums.b = 7.8;
someNums.c = 99.5;
cout<<someNums.a<<endl<<someNums.b<<endl<<coutsomeNums.c<<endl;
dummyFunct(someNums);
cout<<someNums.a<<endl<<someNums.b<<endl<<coutsomeNums.c<<endl;
float one=987.34, two=0.876;
cout << one << " " << two << endl;
funct(one, two);
cout << one << " " << two << endl;
return 0;
}
-Futura