Reading the input file into integer arrays

Hey all,
I have a question about file input processing. I need to read in a file along with my executable in UNIX like so:

Code:

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prompt: a.out  < inputfile

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and I need to get two lines and store each of those lines into integer arrays for manipulation later. How would I go about doing that? Thanks.

So your input file looks like this..

Code:

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12 31 234 53 2 12
234 2 2 212 3

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and you wan to read each row into different arrays?

exactly! Would you know how to?

Hello all,
I have a file that I need to read into my program at the command line. This program should take this input file (e.g. input1) and store it in two different array. This is how my code looks like but it doesn't work. Someone please help.
This is what I would type in order to execute my program:

Code:

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a.out < input1

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This is my input1 file:

Code:

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1 2 3 4 5
1 2 4 4 5

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This is my program:

Code:

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#include <iostream>
#include <string>
#include <fstream>

// Global values and arrays

int preorder[26];
int inorder[26];

int main(int argc, char **argv){
  if (argc != 1){
    // report some error message
    cerr << "Error";
    exit(-1);
  }
 
  char *fileName = argv[2];
 
  cout << argv[2];
 
  // declared an ifstream object
  ifstream in(fileName);
 
  // if in cannot be opened, display error message
  if (!in){
    cerr << "File cannot be opened!\n";
    exit(-1);
  }
 
  // read information into array preorder[]
  int count = 0;
  while ((!(in >> "\n")) || count <= 26){
    cin >> preorder[count];
    cout << preorder[count];
    count++;
  }

  // read information into array inorder[]
  count = 0;
  while ((!(in >> "\n")) || count <= 26){
    cin >> inorder[count];
    cout << inorder[count];
    count++;
  }
 
  return 0;
}

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Someone please help. Thank you.