Finding Average of floats

can some one tell me whats wrong with this program. i'm trying to find average of 10 floats and how do i use code tags?

Code:

---

#include <iostream.h>
#include <iomanip.h>

void main()
{
        // declare all variables
        float a[10];
       
        // ask user for numbers
        cout << "What are the floating point numbers?" << endl;
        cin  >> a[10];
       
        float average;
        average = ((a[1]+a[2]+a[3]+a[4]+a[5]+a[6]+a[7]+a[8]+a[9]+a[10])/10);
        cout << "The average is " << average << endl;
       

}

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I added the code tags for you, but here's how you use them:

put [code] before your code, then [/code] after your code and voila...check the link in my signture for more...

(looks like this when typing)

[code]

cout << "hi";

[/code]

well, first you need to actually get the floats from the user

Code:

---

for(int i = 0; i < 10; ++i)
{
  cout<<"Enter number: ";
  cin>>a[i];
}

---

code tags are

[ code ]
and
[ /code ]

without the spaces.

thank you very much for adding code tags. i haven't used the board since a while and forgot. And thanks for that program help.
Thank you.

Code:

---

#include <iostream.h>

int main()
{
        float a[10];

        cout << "What are the floating point numbers?" << endl;

        for(int i = 0; i < 10; i ++)
        {
                cin >> a[i];
        }

        float average;
        average = ((a[0]+a[1]+a[2]+a[3]+a[4]+a[5]+a[6]+a[7]+a[8]+a[9])/10);
        cout << "The average is " << average << endl;

        return 0;
}

---

Remember the base of an array is 0

Now how would i make the program to display which numbers have exceeded the average?

You can use a conditional statement (like an if...)

that would be pretty simple..

for each score
if score > average
print score is higher than average

I can't resist...

Code:

---

cout << "Numbers that exceed average: ";

for(int j = 0; j < 10; j ++)
{
        if(a[j] > average)
        {
                cout << a[j] << " ";
        }
}

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