Why do this loop stops..!

I have tried to print the Characters.. but loop stops at 20 as i wanted but next it again ask for character hit for each character till 26 ... there it stops completely.... what..is this..

Code:

---


#include <iostream.h>
#include <conio.h>

int main(void)
 {
  clrscr();

  cout<<"Number:\tResult"<<endl;
  cout<<"------:\t------"<<endl;

  for (int i = 0;i<256;i++)
    {
      cout<<i<<":\t"<< char(i)<<endl;
      if(i / 20)
      {
        cout<<"Hit any key to continue...";
        getch();
      }
    }
  cout<<"Asci Chart ended."<<endl;

  getch();
  return 0;
 }

---

Ok, take a look at your statement..

if( i / 20 )

I think you are just trying to be silly with this. It would be much easier to read if you simply put

if( i == 20 )

Your way works...because 20 / 20 = 1, however this may not be immediately intuitive to another programmer. Anyways, when you are in that if statement look at what you are doing. You print out a line, then you wait for a key press. You never do anything to exit the for loop so it just keeps going. If you want to quit , add a break statement after getch( ); So it may look like this.

Code:

---

if( i == 20 ) // two equals for comparison
{
  cout << "Press any key to continue.";
  getch( );
  break;
}

---

Quote:

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Originally posted by MrWizard
Ok, take a look at your statement..

if( i / 20 )

I think you are just trying to be silly with this. It would be much easier to read if you simply put

if( i == 20 )

Your way works...because 20 / 20 = 1, however this may not be immediately intuitive to another programmer. Anyways, when you are in that if statement look at what you are doing. You print out a line, then you wait for a key press. You never do anything to exit the for loop so it just keeps going. If you want to quit , add a break statement after getch( ); So it may look like this.

Code:

---

if( i == 20 ) // two equals for comparison
{
  cout << "Press any key to continue.";
  getch( );
  break;
}

---

---

What do i am intending to do with the if condition that if the loop prints 20 values then it must stop and ask to character input so i can check the output of .. all values... because in my program.... i am using <<endl after every "cout" to display the code and the character...

Okay...well that works when i = 20....because 20 / 20 is 1 which is analagous to true. But when i = 40 you will get 2 as the result... not good! You want

if( i % 20 == 0 )

That will give you every 20th one.

That problem solved.. thanx... but now it stoped at first 0 and then 20 ... but one problem still in the program is that it stops.. at 26... do not displays values till 255 ?????

Your code displayed all of them for me. Take out the break because obviously that isn't what you wanted there. Also change that one line to this...

if( ( i % 20 == 0 ) && ( i != 0 ) )

That'll take care of the case when i is 0.

Thanx.. for help.... but it did not showed after 25...... I 'm using tubro C/C++ 3.0

Dunno what to say then, works fine on mine. Just walk through using a debugger and see whats going on in there! Good Luck!