i can't find what's wrong with this code

Code:

---

#include <stdio.h>

main()
{
  int day_code; /* day_code = 0 means the month starts on Sun
                      day_code = 1 means the month starts on Mon
                      day_code = 2 means the month starts on
                      Tues, etc.  */
  int days_in_month;    /* number of days in month currently
                          being printed */
  int leap_year; /* 1 means leap year; 0 means no leap year */
  int day;      /* counter for day of month */
  int month;    /* month = 1 is Jan, month = 2 is Feb, etc. */

  int year = 0, f = 0, d = 0, c = 0;

  do {
    printf( "Enter year: " );
    scanf( "%d", &year );
    printf ( "%d", &year );
  }while( year < 1776 );

  while ((year % 400 == 0) && (year % 4 == 0) && (year % 100 > 0))
    {
      leap_year = 1;
    }

  c = year / 100;
  printf ( "%d", &c );
  d = year % 100;
  printf ( "%d", &d );
  f = 1 + (( 13 * 11 - 1 ) / 5) + d + ( d / 4 ) + ( c / 4 ) - 2*c;

  printf ( "%d", &f );

  return 0;

}

---

here's whats comes out:

Enter year: 1990
-1073743504-1073743516-1073743512-1073743508



now can anyone please help me and tell me why its giving me all these wacked out numbers?

Code:

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printf ( "%d", &year );
...

---

You're using the adress of operator & in the printf() function. Thereby you are printing the adress of the variable e.g. year.
Remove the "&" in all printf() function calls, recompile and look at the output.

first of all

Code:

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printf("%d", &f ); //wrong

---

What you are trying to do is print the address ???

Code:

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printf( "%d", f );  //this is right

---

Check to code for you leap year ..if it is a leap year then it should print it out where does it do that ....
varaible day_code, month etc... are they just there for fancy ??

Code:

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while ((year % 400 == 0) && (year % 4 == 0) && (year % 100 > 0))
    {
      leap_year = 1;
    }

---

Why are you using a loop here? It's a simple check, so why not just use an 'if' statement?

Code:

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printf ( "%d", &c );
  d = year % 100;
  printf ( "%d", &d );
  f = 1 + (( 13 * 11 - 1 ) / 5) + d + ( d / 4 ) + ( c / 4 ) - 2*c;

  printf ( "%d", &f );

---

You're using printf wrong. You're printing addresses, not values. Don't use the & when using printf.

[edit]Curses! Foiled again.[/edit]
[edit]On a side note, why are you not using hard coded values?

f = 1 + (( 13 * 11 - 1 ) / 5) + d + ( d / 4 ) + ( c / 4 ) - 2*c;

Which is...

f = 1 + ((142)/5) + d + (d / 4) + (c/4) - 2 * c;

Which is...

f = 1 + (28) + d + (d / 4) + (c/4) - 2 * c;

Which is....

f = 29 + d + (d / 4) + (c/4) - 2 * c;
[/edit]

Quzah.