Printing Node Info in Linked List

Hi All,

I'm trying to print information from each node in a linked list.

Here's the code for the print:

Code:

---


if (preloc == NULL)
        cout << start->next << " ";
else
        cout << preloc->next << " ";

---

Here's an example of the output. It's print the address space:

00673174
28
Press any key to continue . . .

00673184
29
Press any key to continue . . .

How do I get it to print the info in the start->next node or preloc->next node?

Any help would be appreciated.

I don't fully understand what you are asking.

If you are asking how to itterate through the linked list elements, do something like this:

Code:

---

current = start;

while(current != NULL)
{
  cout << current;
  current=current->next;
}

---

You are printing the address, but I guess you want to print the actual data in the list. Well, that depends on what variables you use. Say you use a string Name and an integer Age:

Code:

---

NodeE* CurrentNode = FirstNode;

while(CurrentNode != NULL)
{
  cout << CurrentNode->Name << " " << CurrentNode->Age << endl;
  CurrentNode = CurrentNode->NextNode;
}

---

The code prints the address space and not the information in the node. How do deallocate in order to print the node's data rather than the node's address space.

I figured it out. Thanks.