Bitwise operator test - It keeps skipping past a certain point

Hello everyone, I'm currently reading "C++ Weekend Crash Course" by Stephen R. Davis. This is the first book I've read about C++. I'm still learining the basics. Anyways, In the chapter about "Logical Operations" there is a section focusing on "working with binary numbers", "performing bitwise operations", and "creating logical assignment statements". The book provides code for a "bitwise operator test". Here's the part that doesnt seem to work for me.

Code:

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// input the first argument
    int nArg1;
    cout << "Enter arg1 as a four-digit hexadecimal: ";
    cin >> nArg1;
   
//***Right here***   
    int nArg2;
    cout << "Enter arg2: ";
    cin >> nArg2;
   
    cout << "nArg1 & nArg2 =0x"
              << (nArg1 & nArg2) << "\n";
             
    cout << "nArg1 | nArg2 = 0x"
              << (nArg1 | nArg2) << "\n";
             
    cout << "nArg1 ^ nArg2 = 0x"
              << (nArg1 ^ nArg2) << "\n";

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Everytime I run the program it works fine until it gets to the second argument. It skips right past the whole part of the code begining at "int nArg2; cout << "Enter arg2: "; cin >> nArg2;"
and goes right into the next lines of code. Everything looks right to me. I've played around with programs that were more complex then this one and have gotten them working correctly. Any help would be greatly appreciated. I'm using Dev-C++.

Oh and another thing, when I run my compiled programs soon as it gets to the end of the program the DOS prompt closes not giving me enough time to read my programs usally. Anyone know how I can remedy this? I've searched around through Dev-C++ looking for an option that would allow me to keep the programs open even after there finished but couldnt find anything. Thanks.

That runs just fine for me.

If you don't want the console to close, put a getchar() at the end of the program (located in stdlib.h), or preferably getch() (but then you need Borland).

It skips because entering something like "2B5A" into nArg1, will assign 2 to nArg1, as the next character is not numeric. Then when you get to nArg2, "B5A" is left in the input buffer. It then attempts to assign this to nArg2.

I don't think cin will allow you to input a number in hex.. you could try cin.sef(ios::hex), if not, then you may be left to write your own input routine for these hexadecimal numbers... or stick with decimal.

to keep the window open in DEV, add this bevore return:

Code:

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if(getche());

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with

Code:

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#Include <conio.h> // getche();

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at the top.

Quote:

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Originally posted by euphoric

int nArg1;
cout << "Enter arg1 as a four-digit hexadecimal: ";
cin >> nArg1;

---

should be:

Code:

---

    int nArg1;
    cout << "Enter arg1 as a four-digit hexadecimal: ";
    cin >> hex >> arg1;

---

Remember to include <iomanip> or whatever header std::hex is located in.

(edit)I missed Eibro's post(/edit)

Ok, I see what was the problem. I dont really know to much about binary/hexadecimal numbers at the moment. I didn't really understand that chapter to much. Anyone know some good tuts for binary/hex? I guess I the first numbers I was entering in for Arg1 was doing what you said Eibro. I do have this at the top of the program.

Code:

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// set output format to hexadecimal
    cout.setf(ios::hex);

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Thanks for the help everyone. :)