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this function supposed to open all empty spaces..
but it does not work properly..
Code:void openemptyspace(int x, int y)
{
/* Declarations */
int i;
int j;
/* nested for loops and if statments*/
for(i = -1; i <= 1; i++)
{
for(j = -1; j <= 1; j++)
{
if(showmines[x + i][y + j] == '-' )
{
showmines[x + i][y + j] = mines[x + i][y + j];
if(showmines[x + i][y + j] == '0' )
{
openemptyspace(x + i, y + j);
} /* end if */
} /* end outer if*/
} /*end inner for loop */
} /* end outer for loop */
}
>>but it does not work properly..
and? What does it do or not do that makes you think its wrong?
Quote:
Originally posted by jk81
this function supposed to open all empty spaces..
but it does not work properly..
Code:void openemptyspace(int x, int y)
{
/* Declarations */
int i;
int j;
/* nested for loops and if statments*/
for(i = -1; i <= 1; i++)
{
for(j = -1; j <= 1; j++)
{
if(showmines[x + i][y + j] == '-' )
{
showmines[x + i][y + j] = mines[x + i][y + j];
if(showmines[x + i][y + j] == '0' )
{
openemptyspace(x + i, y + j);
} /* end if */
} /* end outer if*/
} /*end inner for loop */
} /* end outer for loop */
}
Usually in recursive functions the recursive part (the part where you call the function again) is not nested within a condition, and the "base case" is in an conditional statement. This style guarentees the the recursive call unless the base case is statisfied. With your style the:
might not get called.Code:if(showmines[x + i][y + j] == '0' )
{
openemptyspace(x + i, y + j);
} /* end if */
cheers