memory location

i was reading a tutorial in c and i found this...

Code:

---


main()
{
 /* copy "hello" into str1. If str1 isn't big enough, hard luck */
 strcpy(str1,"hello");
 /* if you looked at memory location str1 you'd see these byte
    values:  'h','e','l','l','o','\0'
  */

---

what do he mean by... looking at the memory location..... how would i do that...? how can i find out if the values are really hellow \0?

You can print out individual characters.

Code:

---

int main()
{
  int i;

  for ( i = 0; i < strlen(str1); i++ )
      printf( "str1[%d] is %c", i, str1[i] );

}

---

As an extension to Nutshells, you can hex dump the array:

Code:

---

#include <stdio.h>
#include <ctype.h>

#define ARRAY_SIZE 20
int main(void)
{
    char my_string[ARRAY_SIZE] = "hello";
    int i;
   
    for (i = 0; i < ARRAY_SIZE; i++)
    {
        printf ("%02x(%c) ", my_string[i], (isprint(my_string[i])?my_string[i]: ' '));
        if ((i+1) % 10 == 0)
            putchar ('\n');
    }
   
    return 0;
}

/*
Output:

68(h) 65(e) 6c(l) 6c(l) 6f(o) 00( ) 00( ) 00( ) 00( ) 00( )
00( ) 00( ) 00( ) 00( ) 00( ) 00( ) 00( ) 00( ) 00( ) 00( )

*/

---

if you want the memory location, you can do the following:

Code:

---

printf( "%p", &str );

---

if you want to see the values in the array and you have a robust IDE, you can run the debugger and see the values in the array.