Help on toupper string

Hi ... First of all here is my code:
#include<iostream>
#include<fstream>
using namespace std;

int main()
{
int j;
fstream datafile;
char name[81];
datafile.open("demofile.txt",ios::in);

if(!datafile)
{
cout << "File open error!"<<endl;
return 0;
}

while(!datafile.eof())
{
datafile >> name;



for (j = 0; j < 1; j++){
if((name[j] >= 'a') && (name[j] <= 'z')){
*name = toupper(*name);
}
}


cout << name;
}


datafile.close();
cout << "\nDone.\n";
return 0;
}

This code runs perfectly fine , i hve a small problem ... the string which i'm suppose to get as an output is: "Hello. My name is Joe. What is your name ?"
And i'm gettin' :"Hello.MyNameIsJoe.WhatIsYourName?"

Why is it doin' this ??
Please help ..
Thanxs.
:confused:

Well you are not checking for spaces.

Code:

---

for (j = 0; j < 1; j++){
if((name[j] >= 'a') && (name[j] <= 'z')){
*name = toupper(*name);
}
}

---

You also have to check for " " space here.

Ok i got that space thing done, now what about the ouput ... its capitalizing everyword. forexample: Hello. My Name Is Joe.
Plz help.
Thanxs.

Code:

---

#include <cctype>
#include <iostream>
#include <string>
using namespace std;


int main()
{
  string s;

  getline(cin, s);

  typedef string::iterator SI;
  for (SI i = s.begin(); i != s.end(); ++i)
    *i = toupper(*i);

  cout << s << endl;

  return 0;
}

---

Thanxs Nick , but thats not what i want ...

i hve problem with my output ... so if u just scroll up n hve a look at the problem, u will get the idea.

Thanxs anywayz ..

> if((name[j] >= 'a') && (name[j] <= 'z'))
&nbsp; if ( islower(name[j]) )
would be better

> datafile >> name;
This reads a word, not a line.

Use the getline function as suggested by Nick.

You need to consider whether this is the first word on the line, or the first word after a full stop.