Insert char into string?

How can I insert characters into a string?
Example:

Code:

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{R5;;;;1;;1;} ---> {R5;0;0;0;1;0;1;}

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If I´m not wrong it´s like this

Code:

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int main()
{
    char aname[] = "Steve";
    string name = aname;
    cout << name << endl;
return 0;
}

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Or do you mean one character at time???

Code:

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int main()
{
    char aname[] = "Steve";
    string name;
        int size = sizeof(aname) / sizeof(char);
        for (int i = 0; i < (size -1); i++)
                name +=aname[i];

        cout << name << endl;
return 0;
}

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@ ripper079:
I wanted to convert "C1;;;4;;1;" into something that looks like this string: "C1;0;0;4;0;1;".
I tried strtok() but it just removes the ";" and returns: "C1 4 1".
Is there a way to read the string up to a certain character (in this case ";")? After this I need some function to insert the "0" after this position.
Any Idea?

Thank You.

>I wanted to convert "C1;;;4;;1;" into something that looks like this string: "C1;0;0;4;0;1;".
This is hasty, but it should work:

Code:

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#include <iostream>
#include <string>
#include <vector>

template <typename Container, typename ValueType>
Container insert_val ( Container orig, ValueType val, ValueType rep )
{
  std::vector<char> dest;
  std::vector<char>::iterator it = orig.begin();

  while ( it != orig.end() ) {
    dest.push_back ( *it );
    if ( *it == val && *(it + 1) == val )
      dest.push_back ( rep );
    ++it;
  }

  return Container ( dest.begin(), dest.end() );
}

int main()
{
  std::string broken = "C1;;;4;;1;";

  std::string fixed = insert_val ( broken, ';', '0' );

  std::cout<< broken <<std::endl;
  std::cout<< fixed <<std::endl;

  return 0;
}

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-Prelude

Works great. Thanks a lot :)