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I want to generate random number between 1- 400,000 which is not the same value.
Example.
If X1 = 254899
X2 not have the same value as X1.
and X3 not have the same value as X1 and X2 .
I want to generate data X1 - X400,000 which not have the same value and each data have value between 1-400,000
If you know how to do that, please tell me. Thank you.
Random numbers, then just compare the new rand number with what you've already got. If its the same, get another random number.
How long do you reckon that method would be good for Hammer? If you wanted a number between 0 and 100 but no duplicates, when does it take to long to reach the next number because you're throwing away duplicates?
>How long do you reckon that method would be good for Hammer?
Yeah, I suppose I didn't read the original question fully :rolleyes: In answer to your question, not long, I suppose. My theory is good in the short term only. There must be a better way, but it's not coming to me at present... :o
Depends on the situation really. If you want 100 different numbers between 1 and 1000000, then it'll be fine. But if you want 80 random numbers between 1 and 100 a better method would need be to eliminate the 20 random numbers your not going to use. Maybe...
I learned this with a program I wrote that shuffled cards.
This will randomly place the numbers 1-400000 in to 400000 variables without duplicatesCode:int array[400000];
for (int i=1; i<=400000; i++)
{
array[i]=i; // first set each number equal to itself
}
for (int i=1; i<=400000; i++)
{
int x=rand()%400000+1; // pick a random number between 1-400000
// now switch this variable with the variable at the random number generated
int temp=array[x];
array[x]=array[i];
array[i]=temp;
}
on computers its unfortuneate but some things have limits. One of those is the maximum number an int can hold.Also in the example shown RAND_MAX has surely been exceeded too. remember that rand() can only produce values up to RAND_MAX which on my system is 0x7fff