Inline Assembler

In the program I am converting from C to VB, there is what I understand is called "Inline Assembly".

Can someone give me some information on how this is possible or what I could do to accomplish this in another language?

Could they be made into a DLL?

Thanks for any leads!

:)

Inline assembly is when you paste assembler code in your C source by way of a keyword. This is very compiler specific, so it is not portable to use:

Code:

---

int main ( void )
{
  __asm {
    /*
    ** Assembler code goes here.
    */
  }
  return 0;
}

---

I recommend searching google for the details of inline assembly for your compiler and system.

-Prelude

Your example is identical to the what I am seeing in this portion of the C code.

Now knowing that this code is probably not portable, what options do I have for performing the same operation?

Would it be best to build a DLL with these two small functions and make a call, or are there libraries out there that are already suffcient for this?

The Inline ASM is very simple, here it is:

Code:

---

// wait for low
                do
                {
            asm {
            xor        ax,ax
            mov        dx,card_addr
            in        al,dx
            mov        port_data,ax
        }
                } while ((port_data & 0x01) == 1);

// wait for high
        do
        {
            asm {
            xor        ax,ax
            mov        dx,card_addr
            in        al,dx
            mov        port_data,ax
            }
        } while ((port_data & 0x01) == 0);

---

How else could I accomplish the same thing??

Thanks again for your specifics, as they have helped me to understand tremendously.

:)

Quote:

---

The Inline ASM is very simple, here it is:

---

Sure, ASM is simple if you know ASM. Since you're going to VB from C, you naturally don't care about performance. As such, throw together some pseudocode to what the ASM is doing, and turn it into a function.

Quzah.

Cool... I understand and will try and implement this method.

Thanks for your help.

:)