Quick Answer...

I have a pointer.... is there a way to chagne what data type it is?

Like i have 5 structures and i need to use the same variable but be able to switch betwen which type it is in the program. I dont really want to just cast it to another one cuz it get all bloated code. but can i just do someting to delete the current pointer and make it again w/ a different data type?

You could declare a void pointer and then make it point to the appropriate type.

I'm not exactly sure if this is what you want.
Eg.

Code:

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typedef struct{/*...*/}ONE;
typedef struct{/*...*/}TWO;
typedef struct{/*...*/}THREE;
typedef struct{/*...*/}FOUR;
typedef struct{/*...*/}FIVE;

int main()
{
        void *ptr;
        ptr = new ONE;
        delete ptr;
        ptr = new TWO;
        delete ptr;
        ptr = new THREE;
        delete ptr;
        ptr = new FOUR;
        delete ptr;
        ptr = new FIVE;
        delete ptr;
       
        return 0;
}

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You could always redefine the 5 structures as 5 classes that derive from a common base class. A pointer to a class can be assigned to derived classes as well.

Void pointers are handy for passing addresses, but you have to typecast them each time you use them.

OK, I understand your problem now.

If you used that method then you'd have to cast the pointer each time you used it.

Code:

---

int main()
{
        void *ptr;
        ptr = new ONE;
        ((ONE*)ptr)->foo = NULL;
        delete ptr;
        return 0;
}

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You could define a structure that had pointers to the other structures as members.

Code:

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typedef struct{char* foo;}ONE;
typedef struct{char* foo;}TWO;
typedef struct{char* foo;}THREE;
typedef struct{char* foo;}FOUR;
typedef struct{char* foo;}FIVE;

typedef struct
{
        ONE* one;
        TWO* two;
        THREE* three;
        FOUR* four;
        FIVE* five;
}ALL;

int main()
{
        ALL* ptr = new ALL;
       
        ptr->one = new ONE;
        ptr->one->foo    = NULL;
                delete ptr->one;
               
        return 0;
}

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