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Hello,
i am having a debate with a fello college about this one. Can someone set the record dtraight once and for all with this easy queastion?
enum color {red, yellow, green, blue}
QUESTION1:
What is the value of the expression(enum color) ((int)red +2)?
a. 0
b. 1
c. 2
d. green
My answer is C
enum cday {sun, mon,tue,wen,thu,fri,sat}
QUESTION2:
What is the value of the expression(enum day) ((int)thu + 5)% 7)?
a. 2
b. sun
c. mon
d. tue
MY answer is mon.
Later Gator 12%43!&
-c-c-out
>QUESTION1
red is 0, therefore the calculation is 0+2 = 2.
>QUESTION2
thur is 4 (or it would be if you spelt it correctly ;) ), therefore the calc is ((4 + 5 +2)% 7) = 4
Also, because you added 7 (5+2) then mod'ed by 7, you'll always end up with what you started.
That's what I think, at this early hour of the morning :)
How did you get to mon for q2?
Thats simple hammer,
I msispleed the expression.
I meant to say: ((int)(thu + 5)%7)
Now whatcha think all the ways from UK.
>((int)(thu + 5)%7)
thu is still 4, so we have
>(4 + 5)%7
which is
>9%7
equals 2.
Therefore the answer is Tuesday.
That's what I think, all the way from the UK :D