converting string to double

all of you have been very patient in helping me but now Im faced with a problem of integrating code from people who used different styles. I understand how each works but Im not so sure how to get them to work together.

The main part of the program simply collects an array of numbers using double as the type. Someone was kind enough to help me with a simple verification function so invalid characters could not be entered.

Code:

---

//Code by: Prelude

bool validate ( std::string val )
{
  int i, j;
  const std::string valid = "0123456789-.";
  for ( i = 0; i < val.length(); i++ ) {
    for ( j = 0; j < valid.length(); j++ )
      if ( val[i] == valid[j] )
        break;
    if ( j == valid.length() )
      return false;
  }
  return true;
}

---

The problem I have is how can I take my arrary using a double data type and ?convert? it to use this function which uses a string.

try looking up atol.

>>Code by: Prelude

Have you worked any of this out yourself?

>Someone was kind enough to help me with a simple verification function so invalid characters could not be entered. <

There's built in stream member functions to do this, and they'll do the conversion for you -

Code:

---

#include <iostream>

using namespace std;

int main()
{
        double d;

        cin >> d;
        while(cin.fail())
        {
                cout << "char entered ";
                cin.clear();
                cin.ignore();
                cin>>d;
        }

        return 0;
}

---

didn't know about that. what other data types does .fail perform checks on?

hey that works great, the only problem is that if I were to enter something like: RRRR

it would print "char entered" as many times as total characters (4).

>what other data types does .fail perform checks on?<

It's extendable -

Code:

---

#include <iostream>

using namespace std;

class c
{
private:
        int a;
        int b;
public:
        friend istream& operator>>(istream& is,c& rhs){
                return is>> rhs.a >> rhs.b;
        }
};


int main()
{
        c d;

        cin >> d;
        while(cin.fail())
        {
                cout << "char entered ";
                cin.clear();
                cin.ignore();
                cin>>d;
        }

        return 0;
}

---

but fundamentally it only distinguishes between a character and a digit (this is pretty much all you need for the primitive types that it has been pre-defined for)

>the only problem is that if I were to enter something like: RRRR

it would print "char entered" as many times as total characters (4).<

You're allowed to modify it.

easier said than done, but Ill give it my best shot

ta for explaining.

>The problem I have is how can I take my arrary using a double data type and ?convert? it to use this function which uses a string.

Use c_str() (I believe that's it) to get the character array part of the string. Then use atof() to convert to a double.

Code:

---

string val;
double num;
.
.
num = atof(val.c_str());
cout << "num:" << num << endl;

---