arrays and functions (beginner q)

edit since this question is more important than my other now:

Code:

---


void mode( int freq[], int answer[], int size )
{
  int rating, largest = 0, modeValue = 0;

  cout << "\n********\n  Mode\n********\n";

  for ( rating = 1; rating <= 9; rating++ )
      freq[ rating ] = 0;

  for ( int j = 0; j < size; j++ )
      ++freq[ answer[ j ] ];

  cout << "Response"<< setw( 11 ) << "Frequency"
        << setw( 19 ) << "Histogram\n\n" << setw( 55 )
        << "1    1    2    2\n" << setw( 56 )
        << "5    0    5    0    5\n\n";

  for ( rating = 1; rating <= 9; rating++ ) {
      cout << setw( 8 ) << rating << setw( 11 )
          << freq[ rating ] << "          ";

      if ( freq[ rating ] > largest ) {
        largest = freq[ rating ];
        modeValue = rating;
      }

      for ( int h = 1; h <= freq[ rating ]; h++ )
        cout << '*';

      cout << '\n';
  }

  cout << "The mode is the most frequent value.\n"
        << "For this run the mode is " << modeValue
        << " which occurred " << largest << " times." << endl;
}

---

what it basically does is display the types of responses, the frequency at which those responces occurred (it puts that data in a nice tabular format) and alongside a histogram of the data. It then states the mode and its frequency. Now my problem, I'm having trouble with an array of a "tie" of mode values (example: 8 and 9 both occurred 20 times) and it only displays 8 occuring 20 times. How can i fix it so it will display both items or more than two for that matter if there is a more-than-two way tie?

if(size % 2 == 0) //if size is an even number;
double median = (double)((answer[size/2] + answer[((size/2) -
1)])/2);
else
median = answer[size/2];

thanks i modified the code to:

Code:

---


void median( int answer[], int size )
{
  cout << "\n********\n Median\n********\n"
        << "The unsorted array of responses is";

  printArray( answer, size );
  bubbleSort( answer, size );
  cout << "\n\nThe sorted array is";
  printArray( answer, size );
 
  if ( size % 2 == 0) {
          cout << "\n\nThe median elements are " << size / 2
                    << " and " << ( size / 2 ) + 1 << " of\nthe sorted "
                        << size
                        << " element array.\nFor this run the median is "
                        << (answer[ size / 2] + answer [ ( size / 2 ) + 1]) / 2
                        << "\n\n";
  }
  else {

          cout << "\n\nThe median is element " << size / 2
            << " of\nthe sorted " << size
            << " element array.\nFor this run the median is "
            << answer[ size / 2 ] << "\n\n";
  }
}

---

I never would have thought about using mod 2 which is the heart of what i needed :D .

Now i have a different problem. This time im doing mode and here is my code for the function:

Code:

---


void mode( int freq[], int answer[], int size )
{
  int rating, largest = 0, modeValue = 0;

  cout << "\n********\n  Mode\n********\n";

  for ( rating = 1; rating <= 9; rating++ )
      freq[ rating ] = 0;

  for ( int j = 0; j < size; j++ )
      ++freq[ answer[ j ] ];

  cout << "Response"<< setw( 11 ) << "Frequency"
        << setw( 19 ) << "Histogram\n\n" << setw( 55 )
        << "1    1    2    2\n" << setw( 56 )
        << "5    0    5    0    5\n\n";

  for ( rating = 1; rating <= 9; rating++ ) {
      cout << setw( 8 ) << rating << setw( 11 )
          << freq[ rating ] << "          ";

      if ( freq[ rating ] > largest ) {
        largest = freq[ rating ];
        modeValue = rating;
      }

      for ( int h = 1; h <= freq[ rating ]; h++ )
        cout << '*';

      cout << '\n';
  }

  cout << "The mode is the most frequent value.\n"
        << "For this run the mode is " << modeValue
        << " which occurred " << largest << " times." << endl;
}

---

what it basically does is display the types of responses, the frequency at which those responces occurred (it puts that data in a nice tabular format) and alongside a histogram of the data. It then states the mode and its frequency. Now my problem, I'm having trouble with an array of a "tie" of mode values (example: 8 and 9 both occurred 20 times) and it only displays 8 occuring 20 times. How can i fix it so it will display both items or more than two for that matter if there is a more-than-two way tie?

Im thinking that maybe i should include an if statement but im not sure how i could incorperate that to "detect" two modes... After it goes through the frequency loop it totally ignores the other mode and displays one. How can i display two modes????

once you have found the mode, just search through the array again and print out all values that match the mode

Code:

---

for (int i = 0; i < size; ++i) {
  if (freq[i] == largest)
      cout << i << ": " << freq[i] << endl;
}

---