Count the length of strintg without using strlen?

Is there a way to count the characters in a string without using strlen? I was trying to write my own string length function by using the array....Do
I have to initialize the char array? Can someone
just give me a hint please??? Here are part of the
code I have so far, very very ugly.......I don't
even know what am I doing anymore......

#include <stdio.h>
int length(char[]); /* prototypes the function for the length of the char */
char oddeven(int); /* prototypes the function for even or odd char length */
int main(void)


{
int x;
char array[26];
length(array);
x=length(array);
printf("\nThe length of the string is %d characters\n", x);

return 0;

}

int length(char array[]) /* define the function of char length */

{
int i = 0;
/* char array[26];*/ /* 25 characters + 1 for the \0 */
char c;
printf("\nPlease enter a string, maximum of 25 characters;\n");

c = getchar();
while(c != '\0' && c != '\n')
{

array[i++] = c;
return i;
}
}

I change the characters function to:

printf("\nPlease enter a string, maximum of 25 characters;\n");

gets( array );
while(array[i] != '\0' && array[i] != '\n')
{
i++;
return i;
}

Still didn't work it return 1 for the characters length after I type like 13 letters, also it prints out "Please enter a string, maximum of 25 characters" two time. Why????Please help anyone?

thank you...

ok I change a few thing again (can you guys see
I'm trying very hard.. ^__^)

but, when I run the program, 1)I type in few characters hit return, nothing happen, like it's wating for something, so I type it in again, this time it took the string...2)but it also count the "Enter" key that was push by the user after the characters was enter. Can some one help me sove this two problems?

thank you......


int length(char[]); /* prototypes the function for the length of the char */
char oddeven(int); /* prototypes the function for even or odd char length */
int main(void)


{
int x;
char array[26];

printf("\nPlease enter a string, maximum of 25 characters:\n"); <--------
length(array);
x=length(array);
printf("\nThe length of the string is %d characters\n", x);

return 0;

}

int length(char array[]) /* define the function of char length */

{
int i = 0; <------
int c = 0; <------

while (c != '\n') <-------

{
array[i++] = c; <-------
c = getchar(); <-------

}
array[i] = '\0'; <-------
return i;
}
:confused:

Code:

---

#include "stdafx.h"

void Count(char[]);

int main()
{
        char array[25];
        puts("Fill array: ");
        scanf("%24[^\n]",array);
        Count(array);
        return 0;
}

void Count(char a[])
{
        char *ptr = a;
        int count=0;
        while(*ptr != '\0')
        {
                count++;
                ptr++;
        }
        printf("\nSize is %d",count);
}

---

Something like this will work. I'd use a pointer to traverse the array.

Hi Witch_King,

Thank you very much for helping me...
but we can't use pointer, because we have not
cover that in class yet. The teacher want us to
write the two functions and pass the int value
back to main.

void Count(char[]) <---- can't use this too

she want us to use:

int length(char []);
char oddeven(int);

thank you though.....
I think I need to get some sleep.....can't come up with anything anymore in my little dumb dumb brain...

Give me 10 minutes. I'll give you an answer using those functions.

Code:

---

#include "stdafx.h"

int length(char []);
void oddeven(int);

int main()
{
        char array[25];
        int size;
        printf("Enter string: ");
        gets(array);
        size = length(array);
        printf("size is %d",size);
        oddeven(size);
        return 0;
}

int length(char a[])
{
        int count=0;
        while(true)
        {
                if(a[count] == '\0') break;
                count++;
        }
        return count;
}

void oddeven(int size)
{
        if (size % 2)
        {
                printf("\n%d is Odd",size);
        }
        else
                printf("\n%d is even",size);
}

---

I didn't understand why the oddeven returned a character so I changed it but this is the general idea. I would have actually made the array arguement constant because you don't want it changed in the function but it works this way for the purposes of a school assignment.

10 minutes??? oh my god.....How How???
I..I...work on this problem for 3 days already...
>__<...I feel so sorry for myself.....


Thank you... thank you....

I'll try to correct my code again.....

I've sudied C and C++ for 2 years. I have lots of experience. That's the only reason why I can answer this question quickly. You will no doubt still have to make a few adjustments to it though, but you can likely take it from here.

What kind of header is stdafx.h , do we have it on solaris ?


#include <stdio.h>
/*return length of a string*/
int len(char s[])
{
int i=0;
while(s[i]) i++;
return i;
}

/*return 1 if odd and 0 if even */

int isodd(int i)
{
return i&1;
}