Ask about generate Random number

I want to generate random number between 0-1,000,000
but I can not generate random number that have much value because data type int and long do not have much value. If I want random number 0-1,000,000. How can I do that?
Thank you.

code:
.................................................. .................
long i;

srand( (unsigned)time(NULL) );
i = rand()%10000000;
.................................................. .................

Quote:

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Originally posted by ooosawaddee3
I want to generate random number between 0-1,000,000
but I can not generate random number that have much value because data type int and long do not have much value. If I want random number 0-1,000,000. How can I do that?
Thank you.

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Get a new compiler. Integers are (now a days) 32 bits. This produces (signed) a number between -2,000,000,000 and +2,000,000,000.

Try this:

Code:

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#include <stdio.h>
int main ( void )
{
    printf("I have a %d compiler!\n",
        sizeof( int ) == 2 ? 16 :
        sizeof( int ) == 4 ? 32 :
        sizeof( int ) == 8 ? 64 );
    return 0;
}

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Quzah.

Or, you can go about this way, but you might be missing out quite some digits. I'm basically concatenating two 2-byte integers, to form a 4 byte value, large enough to hold your limit: 0 to 10000000

Code:

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#include <stdio.h>
#include <stdlib.h>

int  main(void)
{
        long l;

        srand(65535U);

        while(1) {
                l = ((long)rand() % 65535L) | ((long)rand() % 65535L) << 16;
                l = l % 10000000L;

                printf(" %ld\n", l);
        }

        return(0);
}

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