Can we have a new contest?

Please?

Sure, come up with a way to get the size of a variable without the sizeof operator. The first person to do it gains the admiration of those who didn't do it first. ;)

-Prelude

Deleted due to utter crappiness.:D

Note to Self: Have to sleeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

And did you test this at all? Once I fixed the syntax errors, all it does is loop infinitely. Here's a hint: The answer is simpler than you think (one-liner).

-Prelude

Dual-catfish: do you mean the easy contest?

my entry:

Code:

---

int main() {
  int i=0;
  long x = 1; //change variable type to any other type
  while (x) {  x<<=1; i++; }
  printf("%d bits",i);
}

---

unfortuneately it doesn't do floating point types.

I mean either the easy or the hard, I really depends on what they end up being.

i could be persuaded to change the easy if no-one signs up. but the hard one is already locked in stone.

i'll probably need to hold a poll and restart the easy contest under the new topic if there's a lack of contestants. the two runner-up entries are the bitwise calculator and the slot machine.

who else agrees with this idea?

This is what I had in mind:

Code:

---

#include <stdio.h>

#define SIZEOF(x) (char *)(&x + 1) - (char *)&x

struct test
{
  int a, b, c, d;
  float f;
};

int main ( void )
{
  int i;
  char c;
  float f;
  double d;
  char *a = "This is a test";
  char b[] = "This is a test";
  struct test s;

  printf ( "int: %d\nchar: %d\nfloat: %d\ndouble: %d\n"
          "char *: %d\narray: %d\nstruct: %d\n\n",
          SIZEOF(i), SIZEOF(c), SIZEOF(f), SIZEOF(d),
          SIZEOF(a), SIZEOF(b), SIZEOF(s) );
  printf ( "int: %u\nchar: %u\nfloat: %u\ndouble: %u\n"
          "char *: %u\narray: %u\nstruct: %u\n\n",
          sizeof(i), sizeof(c), sizeof(f), sizeof(d),
          sizeof(a), sizeof(b), sizeof(s) );

  return 0;
}

---

>who else agrees with this idea?
Well, if there are no entries, what else can you do? ;)

-Prelude