String

How can I pass a string to a function??

void myfun( char * stringy );

...

char buf[BUFSIZ];

myfun( buf );

Quzah.

Quote:

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Originally posted by Paninaro
How can I pass a string to a function??

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I suppose the real answer is you can't, you have to pass a pointer to the string, like in the example given.

A simple program to check whether the first or last characters of a string are uppercase...

Code:

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#include <ctype.h>
#include <stdio.h>

#define TRUE 1
#define FALSE 0

int StringStartsWithUpper (char *);
int StringEndsWithUpper (char *);

char * myString = "This is the sample string";

int main (void) {
        printf ("%s\n", myString); // Pass the string to printf

        if (StringStartsWithUpper (myString)) { // Pass the string to this function
                printf ("Starts with an upper case letter.\n");
        } else {
                printf ("Doesn't start with an upper case letter.\n");
        }

        if (StringEndsWithUpper (myString)) { // Pass the string to function
                printf ("Ends with an upper case letter.\n");
        } else {
                printf ("Doesn't end with an upper case letter.\n");
        }

        return 0;
}

int StringStartsWithUpper (char * checkMe) {
        return isupper(checkMe[0]); // Pass a char to isUpper()
}

int StringEndsWithUpper (char * checkMe) {
        int length = strlen (checkMe); // Pass the string to strlen.  Returns the length of the string.
        return isupper (checkMe [length - 1]); // Pass a char to isUpper()
}

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