How do I print a pattern flush right?

Can anyone tell me how to program a pattern to print flush right using only nested for statements. I have been successful getting the star pattern to print flush left, but what do I need to add to have the same pattern print flush right? Here is what the patterns look like flush left.

*
**
***
****
*****
******
*******
********
*********
**********
Flush left
**********
*********
********
*******
******
*****
****
***
**
*

Use a variable to determine how many spaces to print and a variable to determine how many fill characters to print. You can do this with three loops or a trick with printf. Assuming you use the loops, the outer loop will contain two loops that print a series of spaces and fill characters respectively. The outer loop controls how many spaces and fills to print, with each iteration the spaces decrements and the fills increments:

Code:

---

Outer
  Print Space
    print a space
  Loop while more spaces
  Print Fill
    print a fill character
  Loop while more fills
  increment fill
  decrement space
Loop while more spaces
---------
space = 4
fill = 1
    *
space = 3
fill = 2
  **
space = 2
fill = 3
  ***
space = 1
fill = 4
 ****
space = 0
fill = 5
*****

End result:
    *
  **
  ***
 ****
*****

---

-Prelude

Hello Basia. Was your attempt at the code something like my effort?
With a variety of expressions in the for loops, I came up with this:

Code:

---

#include<stdio.h>

#define MAX 10 /*The maximum number of chars in a line*/

int main(void)
{
 int i, j;

 for(i=0; i<MAX; i++)
 {
  for(j=i+1; j>0; j--)
        printf("%c",'*');
        printf("%c",'\n');
  }

 printf("%c",'\n');

 for(i=MAX; i>0; i--)
 {
  for(j=i; j>0; j--)
        printf("%c",'*');
        printf("%c",'\n');
  }

 printf("%c",'\n');

 for(i=0; i<MAX; i++)
 {
  for(j=MAX-i-1; j>0; j--)
        printf("%c",' ');
  for(j=i+1; j>0; j--)
        printf("%c",'*');
        printf("%c",'\n');
  }

 printf("%c",'\n');

 for(i=0; i<MAX; i++)
 {
  for(j=i; j>0; j--)
        printf("%c",' ');
  for(j=MAX-i; j>0; j--)
        printf("%c",'*');
        printf("%c",'\n');
  }

return 0;
}

---

This will produce the four possible patterns.
And good evening to Prelude... (It's 1am in the UK...)
Cheers from Badger!

yeah to print what you want just send all the characters to printer buffer using 'stdprn'


you would have used printf() to print somany "*" on the screen.

now to print them out using a printer.

just convert every printf() that prints " * " on the screen with follwing statement.

printf(" * "); -----> fprintf(stdprn," * ");

you're done,

you won't see the out put on the screen

to see the output on the screen keep both the lines!

okaY.....


bye

sorry i thought that you want them to be printed on a paper by a printer!
here you are again!


#include<stdio.h>
#include<conio.h>

void main()
{
int i,j,k;
int max=9;

clrscr();

for(i=1;i<=max;i++)
{
for(j=1;j<=i;j++)
{
printf("*");
}
printf("\n");
}

printf("\n");

for(i=max;i>=0;i--)
{
for(j=1;j<=i;j++)
{
printf("*");
}
printf("\n");
}

getch();
}

And here another version using the memset function:

Code:

---

#include <stdio.h>
#include <string.h>

#define WIDTH 10

void print_line(int i)
{
        char str[WIDTH+1];
        memset(str, ' ', WIDTH - i);  /* place WIDTH - i spaces in buffer */
        memset(str + WIDTH - i, '*', i);  /* add i stars to buffer */
        str[WIDTH] = 0;  /* make string null terminated */
        printf("%s\n", str);
}

int main()
{
        int i;
        for(i = 1; i < WIDTH; print_line(i++)) ;
        for(i = WIDTH-1; i > 0; print_line(i--)) ;
        return 0;
}

---