Linked list; heelp

How do I continue reading in input even if it encounters a space? Is it possible to get several sentences, save it in a linked list , then output it? In my program everytime a space is encountered, it prints out the input one word at a time, each one a newline, instead of a sentece.
How do I modify it to accept sentences instead of words?
Thanks in advance!

#include <stdio.h>
#include <stdlib.h>

#define MAXNAMELEN 20

typedef struct bdaynode
{
char fname[MAXNAMELEN];
struct namenode *next;
} NameStruct;

typedef NameStruct *NamePtr;

NamePtr newName(void)
{
NamePtr element;

element = (NamePtr) malloc(sizeof(NameStruct));
element->next = NULL;
return(element);
}

void setNameData(NamePtr list, char *fname)
{
strcpy(list->fname, fname);

return;
}

NamePtr getName(void)
{
char fname[MAXNAMELEN];
NamePtr tmp;

printf("Enter person name: ");
if (scanf("%s", fname) == EOF)
return(NULL);

tmp = newName();
setNameData(tmp, fname);
return(tmp);
}

NamePtr insert(NamePtr list, NamePtr element)
{
element->next = list;
return(element);
}

NamePtr insertEnd(NamePtr list, NamePtr element)
{
NamePtr tmp;

if (list == NULL)
return(element);
for(tmp = list; tmp->next != NULL; tmp = tmp->next)
;
tmp->next = element;
return(list);
}

void printName(NamePtr list)
{
NamePtr tmp;

printf("\n");
for(tmp = list; tmp != NULL; tmp = tmp->next)
printf("%s\n", tmp->fname);
return;
}

NamePtr deleteAll(NamePtr list)
{
NamePtr tmp;
for(; list != NULL; list = tmp)
{
tmp = list->next;
free(list);
}
return(NULL);
}

int main(void)
{
NamePtr firstName = NULL, tmp;

while ((tmp = getName()) != NULL)
firstName = insertEnd(firstName, tmp);

printName(firstName);

deleteAll(firstName);

return 0;
}